4x+y=16 multiply both sides by -3 and will get
2x+3y=-2
-12x -3y = -48
2x +3y = -2
--------------------------
-10x 0 = -50
-10x = -50
x = -50/(-10) = 5
x = 5
4x+y=16
4*5+y=16
20+y=16
y = 16-20
y = -4
x = 5
y = - 4
hope helped
Given:
The tens digit of a two digit number is 5 greater the units digit.
If you subtract double the reversed number from it, the result is a fourth of the original number.
To find:
The original number.
Solution:
Let n be the two digit number and x be the unit digit. Then tens digit is (x+5) and the original number is:



Reversed number is:


If you subtract double the reversed number from it, the result is a fourth of the original number.



Multiply both sides by 4.



Divide both sides by 55.


The unit digit is 2. So, the tens digit is
.
Therefore, the original number is 72.
Answer:
two 2
Step-by-step explanation:
First you divide the five over six into the two over three, then you add the quotient of that problem to three over four and the sum is your answer.
I hope this helps you
x^2+2x+8=0
x^2+2x+1+7=0
(x+1)^2= -7
(x+1)^2= i^2.7
x+1= i.square root of 7
x=-1+ i.square root of 7
Answer:
2 2/5
Step-by-step explanation:
12 can go into 5 2 times with a left over of two, so it would be 2 which is 10 and a left over of two. The denominator stays the same. So it would be 2 2/5.