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2 years ago

Find (x,y) such that (8,2)(x,y) = (28,22)

Mathematics

1 answer:

liberstina [14]2 years ago

7 0

Answer:

(x,y) = (3.5, 11)

Step-by-step explanation:

(8,2)(x,y) = (28,22)

Dot product, so:

$(8,2)(x,y) = (8x,2y) = (28,22)$

Then

$8x = 28$

$x = \frac{28}{8} = 3.5$

And

$2y = 22$

$y = \frac{22}{2} = 11$

(x,y) = (3.5, 11)

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If jobs arrive every 15 seconds on average, what is the probability of waiting more than 30 seconds?

Aleksandr [31]

Answer: 0.14

Step-by-step explanation:

Given: Mean : $\lambda=15\text{ per seconds}$

In minutes , Mean : $\lambda=4\text{ per minute}$

The exponential distribution function with parameter $\lambda$ is given by :-

$f(t)=\lambda e^{-\lambda t}, \text{ for }x\geq0$

The probability of waiting more than 30 seconds i.e. 0.5 minutes is given by the exponential function :-

$P(X\geq0.5)=1-P(X\leq0.5)\\\\=1-\int^{0.5}_{0}4e^{-4t}dt\\\\=1-[-e^{-4t}]^{0.5}_{0}\\\\=1-(1-e^{-2})=1-0.86=0.14$

Hence, the probability of waiting more than 30 seconds = 0.14

5 0

3 years ago

PLZ HELP.

Allushta [10]

Answer: c

Step-by-step explanation:

4 0

2 years ago

#1 #2 #3 & #4 thank you

lubasha [3.4K]

I only (sort of) know 3 and 4

3. Andle 1 is an example of an angle bigger than
${90}^{o} c$
I don't know what you call it.

4. If you have a straight line, both angles (or more) added up need to be
${180}^{o} c$
so if angle 1 is 129, 180-129=51
angle 2 is
${51}^{o} c$

If 1 is what is the relationship between the two angles, then maybe the answer is that they both added up need to be 180 degress (?)

And 2 is probably the same as 3 but with angle 2, angle two is an example of an angle smaller than 90 degrees

6 0

3 years ago

Read 2 more answers

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa

KengaRu [80]

Answer:

a. 0.5 or 50%

b. 0.496 or 49.6%

c. 0.8185 or 81.85%

d. Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm

e. 0.0252 or 2.52%

f. The qualifying speed would be 47.4 wpm.

Step-by-step explanation:

a. Let's find the z-score this way:

μ = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

p (z=0) = 0.5 or 50%

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

p (z = -0.01) = 0.496 or 49.6%

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

In consequence,

p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

p = 0.0252 or 2.52%

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

The qualifying speed would be 47.4 wpm.

8 0

2 years ago

What is the value of the expression?

lora16 [44]

-square root 3 over 3
hope this helps.

7 0

2 years ago