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Slav-nsk [51]
3 years ago
12

What solid figure has one base, but no lateral faces?

Mathematics
2 answers:
VLD [36.1K]3 years ago
5 0

Answer:A pyramid is a three-dimensional figure with only one base. The base can be any polygon. The other faces are triangles.

Step-by-step explanation:

stellarik [79]3 years ago
4 0

Answer:

sphere

Step-by-step explanation:

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Pls help due soon ty
Feliz [49]
The first table : y=4x
the second table: y=1.5x
the third table: y= 1.25x

if you want help on how to do it: plug each of those equations into the “desmos” graph! from looking at those table points (x,y) you can find which equation matches the table

for instance on table one: I put y=4x into desmos then looked at graph one, I chose the point (2,8) I went to 2 on the x axis and moved my finger up 8 and that point was directly on the line meaning that table matches the equation. be sure to also do the same thing with the other points to double check!
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4 years ago
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Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Using the formula for area of parallelograrn, find the area of the following parallelograr if
lianna [129]

Answer:

15

Step-by-step explanation:

the formula for area of a parallelogram is base times height

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3 years ago
I need help on 16,17,18,19 please
aev [14]

Answer:

Obtuse stb stb a ad

Step-by-step explanation:

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4 years ago
Hello how are you? Tell me in an answer for 100 points
PIT_PIT [208]

Answer:

Hiiiii

I'm okay, how about you?

thanks for the free points! :)

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