4t=r
a=pir^2
sub 4t for r
a=pi(4t)^2
a=pi16t^2
a(t)=16pi(t^2)
A. a(t)=16pi(t^2)
B. sub 4 for t
a(4)=16pi4^2
a(4)=16pi16
a(4)=16*16*3.14
a(4)=803.84 square units
A. a(t)=16pi(t^2)
B. 803.84 square units
The bisector of angle APQ passes through O and this is illustrated below.
<h3>How to illustrate the information?</h3>
From the information given, the center is O. and the circle passes through O and cuts at K.
In this case, it should be noted that the circles are equal according to the SAS test.
Here, AOB + APQ = 180° (Linear pair)
2AOB = 180
AOB = 90.
Therefore, the bisector of angle APQ passes through O.
Learn more about bisector on:
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Answer:
The number of different computer systems possible is 1440.
Step-by-step explanation:
For each computer, there are 10 options of monitor.
For each monitor, there are 8 printers.
For each printer, there are 2 scanners.
There are 9 computers.
Determine the number of different computer systems possible.
9*10*8*2 = 1440
The number of different computer systems possible is 1440.
Answer:
7^8 =5764801 * 7^3 =343 * 7^4 =2401 ÷ 7^9 = 40353607 * 7^5 =16807
5764801 *343 *2401 ÷ 40353607 *16807
=4747561509943 ÷ 678223072849 = 7
Answer:
B
Step-by-step explanation:
