Answer: x = 3 and y = 1
Step-by-step explanation:
y = - x + 4 ............... equation 1
y = x - 2 ............. equation 2
Solving the linear equation by substitution method , we have :
substitute equation 2 into equation 1 , that is
x - 2 = - x + 4
Add 2 to both sides , we have
x = -x + 4 + 2
Add x to both sides , we have
2x = 6
divide through by 2
x = 3
Substitute x = 3 into equation 2 to find the value of y , we have
y = x - 2
y = 3 - 2
y = 1
Therefore : x = 3 and y = 1
Multiple 6 with 3 and 1 with 2
2/18 = 19
Answer:
34.99
Step-by-step explanation:
22.38 divided by 2= 11.19 24.80 + 11.19= 34.99
hope this helps you :) have a great day and stay safe!
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
Answer:
You will get 13 groups.
Step-by-step explanation:
324 / 24 = 13.5 So there are 13 groups with 5 left over. Hope this helps.
