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lilavasa [31]
3 years ago
5

Find the area of the trapezoid. If the answer is not an integer, leave it in simplest radical form. The figure is not to scale.

Mathematics
1 answer:
Tatiana [17]3 years ago
6 0

Step-by-step explanation:

area of trapezium = 15× 12 + 1/2× 12× 5

= 180 + 30 = 210

<em>plz </em><em>mark</em><em> my</em><em> answer</em><em> as</em><em> brainlist</em><em> plzzzz</em><em>.</em>

<em>hope</em><em> this</em><em> will</em><em> be</em><em> helpful</em><em> to</em><em> you</em><em> </em><em /><em>.</em>

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Solve the following system by any method -8x-8y=0 -8x+2y=-20
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                     \fbox{Solution by using Matrix} 

\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20

\text{Rewrite the linear equations above as a matrix} 

\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right] 

\text{Apply to Row2 : Row2 + Row1} 

\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right] 

\text{ Simplify rows} 

\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right] 

\text{Note: The matrix is now in echelon form.}\text{The steps below are for back substitution.} 

\text{Apply to Row1 : Row1 + 8 Row2} 

\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right] 

\text{ Simplify rows}  

\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right] 

\text{Therefore, the solution is} 

x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}
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