Answer: 0.7
Locate the tenths place which is just to the right of the decimal point. We see a 6 in this spot. Just to the right of this 6 is the value 8. Since 8 is larger than 5, we bump the 6 up to 7 and erase everything else to the right. You can think of it like this
0.687 ---> 0.6 which bumps up to 0.7
This is like saying 687 is closer to 700 than it is to 600
Answer:
a right cylinder with a radius of 7 inches
9514 1404 393
Answer:
- sin(Ф) = (4/41)√41; csc(Ф) = (√41)/4
- cos(Ф) = (5/41)√41; sec(Ф) = (√41)/5
- tan(Ф) = 4/5; cot(Ф) = 5/4
Step-by-step explanation:
The mnemonic SOH CAH TOA can help you with three of the functions. Then you need to remember the relations between those and the other three.
Tan = Opposite/Adjacent
tan(Ф) = 4/5
This suggests you can draw a triangle like the one attached that has adjacent side 5 and opposite side 4. Then hypotenuse can be found from the Pythagorean theorem:
AC² = AB² +BC² = 5² +4² = 41
AC = √41 . . . . . hypotenuse
Then the other trig functions are ...
Sin = Opposite/Hypotenuse
sin(Ф) = 4/√41 = (4/41)√41
Cos = Adjacent/Hypotenuse
cos(Ф) = 5/√41 = (5/41)√41
And the reciprocal functions are ...
csc(Ф) = 1/sin(Ф) = (√41)/4
sec(Ф) = 1/cos(Ф) = (√41)/5
cot(Ф) = 1/tan(Ф) = 5/4
Answer:
x° = 79°
z° = 101°
Step-by-step explanation:
The refrection of a point or set of points across the line y = x will result in a point or set of points whose coordinates are the interchange of the x-value and the y-value of the original point or set of points.
Given that the vertices of a triangle are P(-8, 6), Q(1, -3) and R(-6, -3), the vertices of the triangle formed by the refrection Ry=x<span>(ΔPQR) are P'(6, -8), Q'(-3, 1) and R'(-3, -6).</span>