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AveGali [126]
3 years ago
13

Which are equations? Check all that apply.

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0

Answer:

2,3,4,5

Step-by-step explanation:

sertanlavr [38]3 years ago
6 0

Answer:

2,3,4,5

hope it help

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What are the length and width of a rectangle if the length exceeds the width by 75 inches and the perimeter is 158 inches
olga nikolaevna [1]
Width of 76 inches and length of 3

or width of 77 and length of 2

or width of 78 and length of 1

they all have a perminiter of 158 and all widths exceed 75

8 0
3 years ago
What is a angle called when two angles share a common side and a common vertex
sasho [114]
They are called “Adjacent Angles”
5 0
3 years ago
Read 2 more answers
a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou
Fed [463]

Answer:

\displaystyle P(A)=\frac{6}{11}

Step-by-step explanation:

<u>Probabilities</u>

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

\Omega=\{WW,WN,NW,NN\}

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

A=\{WN,NW\}

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

\displaystyle \frac{5}{11}

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

\displaystyle \frac{6}{10}

Thus the option WN has the probability

\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}

Now for the second option NW. The initial probability to pick a non-white counter is

\displaystyle \frac{6}{11}

The probability to pick a white counter is

\displaystyle \frac{5}{10}

Thus the option NW has the probability

\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}

The total probability of event A is the sum of both

\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}

\boxed{\displaystyle P(A)=\frac{6}{11}}

7 0
2 years ago
Can someone help with problems fivethroughseven
frutty [35]

Answer:

5) 15120

6) 11880

7) 336

Step-by-step explanation:

The formula for permutation where mPn is m!/(m-n)!

Applying this to question 5, we get 9!/4!, which is 15120.

For question 6, we get 12!/8!, which is 11880.

For question 7, we get 8!/5!, which is 336.

5 0
2 years ago
the sum of the ages of a man and his wife is at least 104 years if the man is x years old and the wife is x - 4 years old find t
larisa [96]

Answer:

x ≥ 54

Step-by-step explanation:

x+x-4 ≥ 104

2x ≥ 104 + 4

2x ≥ 108

x ≥ 54

6 0
2 years ago
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