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seraphim [82]
3 years ago
11

Express 1 min as a repeating decimal part of an hour.

Mathematics
1 answer:
alex41 [277]3 years ago
4 0
One minute as a decimal part of an hour is 0.01666667

To find this I divided 1 by60
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Jasmine has to mix 3/4 cup of flour and 3/8 cup of cornmeal she has a container that holds 1 cup can jasmine mix the flour and c
Sladkaya [172]
Because 3/4 and 3/8 is more than one cup, Jasmine will not be able to mix the flour and the cornmeal in the container.

3/4+3/8=6/8+3/8=9/8
5 0
3 years ago
Read 2 more answers
Pls pls pls help <br>Find the perimeter and the area​
Illusion [34]

Answer:

Perimeter = 42 units Area = 57.73 square units

Step-by-step explanation:

Perimeter of an Astroid = 6l ---> 6 x 7 = 42 units

Area of an Astroid = (3 x pi x a^2)/8 = 57.73 square units

3 0
3 years ago
Find the area of a circle with radius, r = 76cm.<br> Give your answer rounded to 3 SF.
PSYCHO15rus [73]

Answer:

17,700.00

Step-by-step explanation:

Area of a circle = 22

------ r2

7

=22

------ 76x76 =123,750

7 ---------- =1,768.571

7

1,768.571 rounded to 3 SF=17700.00

5 0
2 years ago
12(3w+8)=25 what is the w
Mashcka [7]
12(3w+8)=25
36w+96=25 ( I used the distributive property)
          -96 . -96
36w=-71
w=-1.972222.... ( I divided both sides by 36)
 


         

7 0
4 years ago
Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
3 years ago
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