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Masteriza [31]
3 years ago
11

Which answer includes the intrevals that contain the solution to the inequality x^2-1/3x+9<0

Mathematics
1 answer:
victus00 [196]3 years ago
4 0

Answer:

x<±1 and x< -3

Step-by-step explanation:

Given the inequality x^2-1/3x+9<0, we are to find the values of x that satisfies the inequality

x^2-1/3x+9<0

x^2-1/3x+9 (3x+9)²<0*  (3x+9)²

(x^2-1)(3x+9) < 0

x²-1 < 0 and 3x + 9 <0

x²-1 < 0

x²<1

x<±√1

x<±1

Also 3x + 9 <0

3x < -9

x < -9/3

x < -3

Hence the required values of x are x<±1 and x< -3

You might be interested in
Two mechanics worked on a car. The first mechanic worked for 15
nevsk [136]

Answer: For the sum of 130

First: $90

Second: $40

Step-by-step explanation:

We write equations for each part of this situation.

<u>The Total Charge</u>

Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.

<u>The Sum of the Rates</u>

Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.

We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.

For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.

15a + 5 (130-a)=1550

15a+650-5a=1550

10a+650-650=1550-650

10a=900

a=$90 was charged by the first mechanic.

We substitute to find the second mechanic's rate.

90+b=130

90-90+b=130-90

b= $40 was charged by the second mechanic

5 0
2 years ago
PLEASE HELP ITS URGENT!
Rudik [331]

Answer:

A

Step-by-step explanation:

The two equations are similar, because if you multiply the first one by 3 it will be equal to the second one, so when that happens we say that there are infinite solutions.

8 0
2 years ago
HELP PLZZ will give brainliest &lt;3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0
3 years ago
Answer quickly please
KIM [24]

The correct answer is C.


You can tell this by factoring the equation to get the zeros. To start, pull out the greatest common factor.


f(x) = x^4 + x^3 - 2x^2


Since each term has at least x^2, we can factor it out.


f(x) = x^2(x^2 + x - 2)


Now we can factor the inside by looking for factors of the constant, which is 2, that add up to the coefficient of x. 2 and -1 both add up to 1 and multiply to -2. So, we place these two numbers in parenthesis with an x.


f(x) = x^2(x + 2)(x - 1)


Now we can also separate the x^2 into 2 x's.


f(x) = (x)(x)(x + 2)(x - 1)


To find the zeros, we need to set them all equal to 0


x = 0


x = 0


x + 2 = 0

x = -2


x - 1 = 0

x = 1


Since there are two 0's, we know the graph just touches there. Since there are 1 of the other two numbers, we know that it crosses there.

4 0
3 years ago
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An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in Texas. Suppose that the
Arisa [49]
The answer is 50%...
5 0
2 years ago
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