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3 years ago

Which answer includes the intrevals that contain the solution to the inequality x^2-1/3x+9<0

Mathematics

1 answer:

victus00 [196]3 years ago

4 0

Answer:

x<±1 and x< -3

Step-by-step explanation:

Given the inequality x^2-1/3x+9<0, we are to find the values of x that satisfies the inequality

x^2-1/3x+9<0

x^2-1/3x+9 (3x+9)²<0* (3x+9)²

(x^2-1)(3x+9) < 0

x²-1 < 0 and 3x + 9 <0

x²-1 < 0

x²<1

x<±√1

x<±1

Also 3x + 9 <0

3x < -9

x < -9/3

x < -3

Hence the required values of x are x<±1 and x< -3

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4 years ago

(6v^3+42v)/(2v^2+26v+84)

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Answer:
_______________________________________________
The simplied version is:
_______________________________________________
" $\frac{3v(v^2+7)}{(v^2+13v+42)}$ " ;

or; write as: " $\frac{3v(v^2+7)}{(v+7)(v+6)}$ " .
_______________________________________________
Explanation:
_______________________________________________
Given:
_______________________________________________
" $\frac{6v^3 +42 v}{2v^2 +26v + 84}$ " ;
_______________________________________________
→ Factor out a "6v" $\frac{6v(v^2+7)}{2(v^2+13v+42)}$ in the "numerator"; & factor out a "2" in the denominator; as follows:
____________________________________
→ $\frac{6v(v^2+7)}{2(v^2+13v+42)}$ ;
____________________________________
→ " $\frac{3v(v^2+7)}{(v^2+13v+42)}$ " ;
______________________________________________

or; factor out the "denominator" :
______________________________________________
→ (v² + 13v + 42) = (v+7)(v+6) ;
______________________________________________
and write as:
______________________________________________
→ " $\frac{3v(v^2+7)}{(v+7)(v+6)}$ " .
______________________________________________

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4 years ago

A principal of $750 is invested in an account at 9% per year simple interest. What is the account total after 5 years?

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