What is the surface area of a cube that is 2 inches wide, 8 inches long, and 10 inches tall
1 answer:
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Answer:
= 20n + 12
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 52 - 32 = 72 - 52 = 92 - 72 = 20
This indicates the sequence is arithmetic with explicit formula
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 32 and d = 20, thus
= 32 + 20(n - 1) = 32 + 20n - 20 = 20n + 12