What is the surface area of a cube that is 2 inches wide, 8 inches long, and 10 inches tall
1 answer:
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Answer:
Step-by-step explanation:
height of a triangle=4x-1
base=5x+2x-3
=7x-2
area of triangle=base*height/2
=(7x-2)(2x-3)/2
=7x*2x-7x*3-2*2x+2*3/2
=14x^2+21x-4x-6/2
=14^2+17x-6/2
area of rectangle=l*b
(7x-2)(4x+1)
7x(4x+1)-2(4x+1)
4x*7x+7x*1-2*4x-2*1
=28x^2+7x-8x-2
=28x^2-x-2
area of shaded part=area of rectangle-area of triangle
=
Answer:
2. 4x = 7x - 21
Step-by-step explanation: