Answer:
good luck cause i dont know
Step-by-step explanation:
heheh
Answer:
1. 424
2.471
3.512
Step-by-step explanation:
1. 10×12+8×10+8×13+8×15
=120+80+104+120
=424
2. 5×24+9×24+9×15+9×15
=120+216+135
=471
3. 24×16+2×24+2×20+2×20
=384+48+40+40
=512
Answer:
<em>39 is 26.71% of 146</em>
Step-by-step explanation:
Percentage solution with steps:
Step 1: We make the assumption that 146 is 100% since it is our output value.
Step 2: We next represent the value we seek with x.
Step 3: From step 1, it follows that 100% = 146.
Step 4: In the same vein, x% = 39.
Step 5: This gives us a pair of simple equations:
100% = 146(1).
x%=39(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS (left hand side) of both equations have the same unit (%); we have
100/x% = 146/39
Step 7: Taking the inverse (or reciprocal) of both sides yields
x% / 100% = 39/146 ⇒ x= 26.71%
Therefore, 39 is 26.71% of 146.
<em>hope it helps:)</em>
Answer:A,D,E
Step-by-step explanation:
Just did the assignment
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
