Answer:
1%
Step-by-step explanation:
Given : You have used the significant level of 0.01 to estimate the average hours of television viewing for the NJ students.
To Find :What is the chance that our interval estimate does not contain the true population mean?
Solution:
We are given that You have used the significant level of 0.01 to estimate the average hours of television viewing for the NJ students.
So, α=0.01
Significance level indicates a risk of concluding that a difference exists when there is no actual difference.
So, The chance that our interval estimate does not contain the true population mean is 0.01
So, The chance that our interval estimate does not contain the true population mean is 
Hence Option D is true
Answer:
D
Step-by-step explanation:
Answer:
y = -0.07x2 + 3.07x
Step-by-step explanation:
For each plant we add, there is a decrease of 70 grams for all plants from the inicial value of 3 kg of beans.
So, for 2 plants, we have (3 - 0.07) * 2
For 3 plants, we have (3 - 2*0.07) * 3
For x plants, we have (3 - (x-1)*0.07) * x
So we can model the final result of the amount of beans 'y' with the equation:
y = (3 - (x-1)*0.07) * x
y = (3 - 0.07x + 0.07) * x
y = (3.07 - 0.07x) * x
y = -0.07x2 + 3.07x
(In this equation we have a = -0.07, b = 3.07 and c = 0)
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Step-by-step explanation:
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