Answer:
Maybe 0.6
Step-by-step explanation:
Answer:
0.47 and 11.53
Step-by-step explanation:
h = 60t − 5t²
27 = 60t − 5t²
5t² − 60t + 27 = 0
Quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
t = [ -(-60) ± √((-60)² − 4(5)(27)) ] / 2(5)
t = (60 ± √3060) / 10
t = 0.47 or 11.53
Answer:
11/50
Step-by-step explanation:
The frequency numbers for landing on 1, 2, and 3 are:
25, 53, 62.
We add them up to get: 25 + 53 + 62 = 140
Since 250 spins were made, and 140 of them landed on 1, 2, or 3, then
250 - 140 = 110,
so 110 landed on 4 or 5.
We are told the numbers of spins landing on 4 and 5 are equal, so
110/2 = 55,
so the spinner landed 55 times on 4 and 55 times on 5.
relative frequency = 55/250 = 11/50
Answer:
Choice B.
Step-by-step explanation:
2.98 divided by 6 = 0.4966∞ (rounded to the nearest hundredths) 0.50
7.18 divided by 13 = 0.5523076923 (rounded to the nearest hundredths) 0.55
The difference is 5 cents.
~~~Hope this helps~~~ :)