to inverse a equation make all y's x and andy x's y
Thus the inverse is
x=4y-8
Evaluated to
4y=x+8
y=
4x²+4x-35=0
factor: (2x+7)(2x-5)=0
2x+7=0, or 2x-5=0
2x=-7 or 2x=5
x=-3.5 or x=2.5
I don't see any rounding necessary in this case.
when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way:
2 -5
2 7
then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.
if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right.
I hope this makes sense to you.
Well, following the order of PEMDAS, I got choice B. 52
For instance, when you plug in 5 for x, you get F(5)=2(5)^2+2.
Moreover, following PEMDAS, you're supposed to solve what's inside the parenthesis, but since there is no operation going on inside the parenthesis, then you simple move on to the exponent.
In this case, you square the number 5, which gives you F(5)=2(25)+2
After that, you Multiply (letter M in PEMDAS). This results in F(5)=50+2.
Finally, you add them, which results in F=52.
By the way, I noticed a mistake in your work. When multiplying 2 by 5, the answer is 10, not 20.
Anyway, hope this helped! :-)
Answer:
4/3
Step-by-step explanation:
Answer:
Step-by-step explanation:
37
