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3 years ago

How do i write the difference of a number x and 2 is 7 as an equation

Mathematics

1 answer:

HACTEHA [7]3 years ago

5 0

You can quiet literally write the question as it is.

The difference of a number x and 2 is 7.

The difference of a number x and 2 can be written as x-2

is can be written as equal or =

This statement can be translated as x-2=7.

It is as simple as that!

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Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Select three options. 8(x2 + 2x +

AnnyKZ [126]

The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.

<h3>Quadratic equation</h3>

8x² + 16x + 3 = 0

8x² + 16x = -3

8(x² + 2x) = -3

Using completing the square

8(x² + 2x + 1) = -3 + 8

factorization

8(x² + 1) = 5

(x² + 1) = 5/8

Taking the square root of both sides

(x + 1) = ± √5/8

x = -1 ± √5/8

Therefore,

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

Learn more about quadratic equation:

brainly.com/question/1214333

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4 0

2 years ago

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

3 years ago

Helpppppppppppppppp it is due now

Fudgin [204]

Hey mate hope its help you...

5 0

3 years ago

Read 2 more answers

Can you check my answers and help with number 3?

mamaluj [8]

Answer: Question 1 :B,D.

Question 2:option B,

Question 3:Degree=5.

Question 4:option D.

Question 5: option c.

Step-by-step explanation:

1) A polynomial can not have any exponent as a variable or a fraction.

Options B and D are polynomials.

2) The polynomial is having 3 terms and is of degree 3.so it is a cubic trinomial Option B.

3) Degree is the highest power of the variables in the terms .The term $6x^{3} y^{2}$ has the power=3+2=5

So degree =5.

4) $(5x-2+3x^{2} )+(4x+3)=3x^{2} +5x+4x-2+3=3x^{2}+9x+1.$

Option D

5) $(5x^{2} +2x-5)-(3x^{2}+3x+1)= 5x^{2}+2x-5-3 x^{2}-3x-1$

Simplifying like terms,

= $2x^{2}-x-6.$

Option c.

6 0

2 years ago

What type of number cannot be written as a fraction p/q, where p and q are integers and q is not equal to zero

Schach [20]

That is the definition of a irrational number, A rational number must be able to be written as a ratio of 2 integers. The denominator cannot be 0, because that would make the number undefined

8 0

3 years ago

Read 2 more answers