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KIM [24]
3 years ago
10

Since the area under the normal curve within two standard deviations of the mean is 0.95, the area under the normal curve that c

orresponds to values greater than 2 standard deviations above the mean is 0.05.
a. True
b. False
Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

X \sim N (\mu ,\sigma)

And for this case we know this condition:

P(\mu-2\sigma

By the complement rule we know that:

P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05

But since the distribution is symmetrical we know that:

P(X\mu +2\sigma) = 0.025

So then the statement for this case is FALSE.

b. False

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

For this case if we define the random variable of interest X and we know that this random variable follows a normal distribution:

X \sim N (\mu ,\sigma)

And for this case we know this condition:

P(\mu-2\sigma

By the complement rule we know that:

P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05

But since the distribution is symmetrical we know that:

P(X\mu +2\sigma) = 0.025

So then the statement for this case is FALSE.

b. False

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3 0
3 years ago
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
Prime factorization of 52​
lara [203]

Answer:

The first prime factor we test is 2:

52 / 2 = 26

26 / 2 = 13

13 is a prime number so the prime factorization is

2 * 2 * 13 = 52

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Will give brainliest!!
Inessa05 [86]
It’s actually B Bc the little 1 by the 10 is meaning that you are gonna multiply 10x10 one time. Then multiply by 7. 10x10=100 100x7=700 so there for your answer is B
4 0
3 years ago
Multiplying desimals​
kolezko [41]

Answer:

Line up the numbers on the right - do not align the decimal points.

Starting on the right, multiply each digit in the top number by each digit in the bottom number, just as with whole numbers.

Add the products.

Step-by-step explanation:

7 0
2 years ago
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