Answer : - Symmetric property of equality tells that for all real numbers p and q, if p=q then q=p which means if we interchange the sides of an equation then the equation is still a true statement .
For example :-
1. We know that 4+5 =9 then by symmetric property we can also say that 9=4+5.
2. If 5x+5=7 then by symmetric property of inequality 7=5x+5.
Answer:what grade is this for?
Step-by-step explanation:
?
AB = 1/2
BC = -2
CD = 1/2
DA = -2
Answer:
It takes 2.8 seconds for the ball to fall 215 ft.
Step-by-step explanation:
We are given a position function s(t) where s stands for the number of feet the ball has fallen, so we have to replace s with the given value of 215 ft and solve for the time t.
Setting up the equation.
The motion equation is given by

We can replace there s = 215 ft to get

Solving for the time t.
From the previous equation we can move all terms in one side to get

At this point we can solve for t using quadratic formula.

where a, b and c are the coefficients of the quadratic equation

So we get

Replacing on the quadratic formula we get

Using a calculator we get

Physically speaking the only result that makes sense is to move forward in time that give us t = 2.8 seconds.
We can conclude that it takes 2.8 seconds for the ball to fall 215 ft.
Answer:
140
Step-by-step explanation:
To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.
First, let's count the number of subsets that contain the element 3.
Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is
.
Now, let's count the number of subsets that contain the element 4.
4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in
ways.
We conclude that there are 70+70=140 required subsets of S.