SOMEONE HELP PLEASE I DONT WANNA FAIL

Select the answer choice below that represents 5.9 x 10-4 in standard notation.

PIT_PIT [208]

This means that you have to move the decimal point 4 decimal places to the left, as denoted by the negative sign. Thus, this would add 3 zeros before 5. The answer would be 0.00059.

I hope the explanation was clear to you. Have a good day.

6 0

2 years ago

PLEASE HELP IS IT A B C OR D PLEASE HELP ME Thank You

Savatey [412]

Answer: I believe the correct answer is option D.

7 0

2 years ago

Read 2 more answers

How many square inches are in 8 square feet? brainliest if u are right.

Katen [24]

Theres 12 inches in a foot. So 12x8=96

7 0

3 years ago

HELP! I don't understand so please give a detailed explanation.

likoan [24]

From the picture, we can see that ΔLSP and ΔLRN are similar, so corresponding sides are proportionate:

LN : LP = 28:12 = 7:3

Therefore, the LRN sides is 7/3 of the corresponding side of LSP.

Then, it states that the area of LSP = 50, and area of a triangle is (1/2)bh, so we set up the equation

Area of LSP = (1/2)bh = 50 ← Remember how the corresponding sides are 7/3 of LSP? Therefore, the area of LRN:

LRN = (1/2)(7b/3)(7h/3) ← Take out the 7/3 and multiply them together

= (49/9)(1/2)bh ← From LSP, we know that (1/2)bh = 50, so plug that in

= (49/9)*50 ≈ 272.222 units ²

6 0

3 years ago

To test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the value of t

ivolga24 [154]

Answer:

$p_v =P(t_{(29)}>1.42)=0.0831$

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

Step-by-step explanation:

Information given

We want to verify if he mean IQ of employees in an organization is greater than 100 , the system of hypothesis would be:

Null hypothesis: $\mu \leq 100$

Alternative hypothesis: $\mu > 100$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic calculated for this case $t_{calc}= 1.42$

The degrees of freedom are given by:

$df=n-1=30-1=29$

Now we can find the p value using tha laternative hypothesis and we got:

$p_v =P(t_{(29)}>1.42)=0.0831$

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

5 0

3 years ago