2 years ago

Please hellp!! solve

2 answers:

6 0

A the top choice Hope this helps :)

Message me for more help

6 0

Answer:

The top choice (Don't brainliest me Brainliest him i still not become ambitious so brainliest him)

Step-by-step explanation:

#CarryOnLearning

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klio [65]

The remaining balances in the first and second account are $5805 and $1020 respectively.

Explanation

Suppose, the initial balance in the first account was $x$ dollar.

As the total amount in two accounts was $9000, so the initial balance in the second account was $(9000-x) dollar$

He withdrew 10% from the first and 60% from the second account to buy the ring which cost $2175. So, the equation will be......

$0.10x+0.60(9000-x)=2175\\ \\ 0.10x+5400-0.60x=2175\\ \\ -0.50x= 2175-5400= -3225\\ \\ x=\frac{-3225}{-0.50}= 6450$

So, the initial balance in the first account was $6450 and in the second account was ($9000 - $6450)= $2550

Thus, the remaining balance in the first account = 90% of $6450 = $(0.90*6450)= \$5805$

and the remaining balance in the second account = 40% of $2550 = $(0.40*2550)=\$1020$

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2 years ago

Maru [420]

I think it is 39.8 I hoped I helped

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3 years ago

Lina20 [59]

I’m pretty sure the answer is B

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