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Daniel [21]
3 years ago
12

Last year,Mark was 46 inches tall.This year,Marks height is 3 inches less than peters height.Peter is 51 inches tall.How tall is

mark?
Write an equation to represent the situation.
Then solve the equation to answer the problem. I am so confused on this question. Can anyone help me?
Mathematics
1 answer:
alexandr1967 [171]3 years ago
5 0
So mark is 49 inches and the equation is 51-49.Very Simple
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Write in standard form the equation of a line with a slope of -3/5 and a y intercept of -3
Vlada [557]

Answer:

5y+3x=-9

Step-by-step explanation:

Let us start by the general form of the standard equation, Ax+By=C. One way we can solve this problem is by finding the <u>slope-intercept form</u> of this equation, y=mx+b, and converting it into the standard equation. In the slope-intercept form, m represents the slope, b represents the y intercept.

From this problem, we are given both the slope and the y intercept. We know have the equation:

y=-\frac{3}{5}x -3

Great! Now let us rearrange the terms so that the y and x terms are on one side of the equation.

y+\frac{3}{5} x=-3

This seems right, but a standard equation must have coefficient values that are real numbers. So, A and B must be real numbers. We can do this by multiplying the entire equation by 5 and ridding the denominator of the A term.

5y+3x=-9

<em>I hope this helps! Please let me know if you have any questions :)</em>

7 0
3 years ago
If the spinner lands on green 10 times out of 60 spins,which statement true
IrinaVladis [17]

Answer:

  • The spinner lands on green 5 times less than expected

Step-by-step explanation:

Since not provided, it is assumed that the spinner has 4 colors.

Probability of green is one out of four = 1/4

<u>Probability of green out of 60 spins:</u>

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As spinner lands on green 10 times, then it is 5 times less than expected.

<u>Answer:</u>

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Step-by-step explanation:

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Answer:

Correct Answer is 1 Only 5 x 2 5x2 is the second-degree term. Hence, the correct option is (1)

note :

hope i helped

3 0
3 years ago
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