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goblinko [34]
3 years ago
13

Solve the formula for a,the acceleration due to gravity

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0
A= the amount of gravity
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-7.5x + 0.25 = -5.75 <br> The value of x is =
VashaNatasha [74]

Answer:

x = 4/5

I hope this helps!

3 0
3 years ago
Read 2 more answers
If EF=9x+14, FG=56, and EG=250, find the value of x.
nexus9112 [7]

Answer:

Value of x =20

Step-by-step explanation:

Given: EF = 9x+14 units , FG = 56 units and EG = 250 units.

Segment Addition Postulates states the following for 3 points that are collinear.

i.e, Let three points A, B and C are collinear and B is between A and C.

i,e AC = AB + BC

By Segment addition postulates; solve for x;

EG = EF + FG

Substitute the given values we get;

250 = 9x + 14 + 56

or

250 = 9x + 70

Subtract 70 on both sides we get;

250 -70 = 9x + 70 -70

Simplify:

180 = 9x

Divide both sides by 9 we get;

\frac{180}{9} = \frac{9x}{9}

Simplify:

x = 20

Therefore, the value of x =20


7 0
3 years ago
Read 2 more answers
Ill give brainliest <br> Triangle Sum Theorem CLASSWORK
zepelin [54]

Step-by-step explanation:

Sum of angles in a triangle = 180°.

Question 3:

We have 90° + 61° + (14x + 1)° = 180°.

=> 14x° + 152° = 180°

=> 14x° = 28°

=> x = 2.

Question 4:

We have 70° + 55° + (4x + 3)° = 180°.

=> 4x° + 128° = 180°

=> 4x° = 52°

=> x = 13.

7 0
3 years ago
Read 2 more answers
Please help me out with this
Genrish500 [490]

Answer:

x = 17

Step-by-step explanation:

For the parallelogram to be a rhombus then then the diagonal must bisect the given angle, thus

3x - 11 = x + 23 ( subtract x from both sides )

2x - 11 = 23 ( add 1 to both sides )

2x = 34 ( divide both sides by 2 )

x = 17

7 0
3 years ago
Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.
natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is y=x-x^2-2  and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

y'=1-2x

It can be written as

\frac{dy}{dx}=1-2x

Use variable separable method to solve this differential equation.

dy=(1-2x)dx

Integrate both the sides.

\int dy=\int (1-2x)dx

y=x-2(\frac{x^2}{2})+C                  [\because \int x^n=\frac{x^{n+1}}{n+1}]

y=x-x^2+C              ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

-2=1-(1)^2+C

-2=1-1+C

-2=C

The value of C is -2. Substitute C=-2 in equation (1).

y=x-x^2-2

Therefore the solution of the given initial value problems in explicit form is y=x-x^2-2 .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0
3 years ago
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