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goblinko [34]
3 years ago
13

Solve the formula for a,the acceleration due to gravity

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0
A= the amount of gravity
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Please help Ill give brainy pleas help please -
mars1129 [50]
The answer to this is a=3
4 0
2 years ago
Which expression is equal to p + (q + r)?
Verdich [7]
The answer is letter B.
5 0
3 years ago
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It's not a college assignment!
Kisachek [45]

Using a calculator, the equation for the line of best fit where x represents the month and y represents the time is given by:

a. y = −1.74x + 46.6

<h3>How to find the equation of linear regression using a calculator?</h3>

To find the equation, we need to insert the points (x,y) in the calculator.

For this problem, the points (x,y) are given as follows, from the given table:

(1, 46), (2, 42), (3,40), (4, 41), (5, 38), (6,36).

Hence, inserting these points in the calculator, the equation for the line of best fit where x represents the month and y represents the time is given by:

a. y = −1.74x + 46.6

More can be learned about a line of best fit at brainly.com/question/22992800

#SPJ1

8 0
1 year ago
A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula
Ilia_Sergeevich [38]

Answer: A. A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}

              B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

A=\pi.r^{2}

So to find the rate of the area:

\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}

\frac{dA}{dr} =2.\pi.r

Using r(t)=3-\frac{363}{(t+11)^{2}}

\frac{dr}{dt}=\frac{726}{(t+11)^{3}}

Then

\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]

\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}

Multipying and simplifying:

\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}

The rate at which the area is increasing is given by expression A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}.

B. At t = 5, rate is:

A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}

A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}

A'(5)=\frac{2408693760\pi}{4294967296}

A'(5)=1.76268

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0
2 years ago
In order to avoid staying after work, a quality control analyst inspects the first 100 items produced that day. Which sampling m
mr_godi [17]
Based on the given scenario above wherein the quality control analyst just inspects the first 100 items produced that day in order to avoid staying after work, the sampling method that she used is the CONVENIENCE SAMPLING METHOD. Hope this helps.
3 0
3 years ago
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