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Kamila [148]
3 years ago
15

As Jack pulls his wagon down the street it moves faster and faster. Jill, sitting a few meters ahead on the sidewalk, wants to s

low Jack's wagon down so that it travels with a constant speed. How can Jill accomplish her goal?
Physics
1 answer:
Oduvanchick [21]3 years ago
4 0

Answer:

D) She can pull the wagon in the opposite direction with a force equal to Jack's.

Explanation:

If you exert a force that is equal to that of another force being applied to an object, the object will not be accelerating. Since Jack is pulling the wagon faster and faster, the object is accelerating, but if Jill exerts the same force as Jack is exerting, the object would be balanced and have no Newtons acting on it allowing it to move at a constant speed. All the other options would cause for an acceleration or deceleration to take place. If she sat in the wagon, it would not move at a constant speed, if she pushed Jack away from the wagon so that he is not pulling on it anymore, the wagon would decelerate and if she pulled the wagon toward her with twice the force, it would accelerate in her direction.

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The air also contained a small amount of argon
AysviL [449]

The argon molecules become solid when the temperature decrease from 20C to -190 C.

<h3>What changes occur in argon?</h3>

The changes in arrangement and movement of the particles of the argon occurs as the temperature of the air decreased because the argon gas begins to freeze. The freezing point of argon is -189 Celsius so when the temperature decrease from 20C to -190 C, the argon molecules becomes solid.

So we can conclude that the argon molecules become solid when the temperature decrease from 20C to -190 C.

Learn more about argon here: brainly.com/question/23949935

#SPJ1

3 0
2 years ago
A skater of mass 40 kg is carrying a box of mass 5 kg. The skater has a speed of 5 m/s with respect to the floor and is gliding
Yuki888 [10]

For the part a) we need only the momentum of the box and we have the data to find it.

Momentum is given by,

p=mv

where clearly, p is the momentum, m the mass of the box and v is the velocity.

Substituting,

p=(5kg)(5m/s)\\p=25kg.m/s

For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,

p=(5kg)(5m/s)\\p=25kg.m/s

<em>It is the same that part a)</em>

8 0
3 years ago
Why is rust different from the iron and oxygen that it is made of
borishaifa [10]
For the same generic reason that table salt doesn't taste or behave
like the corrosive sodium or the poisonous chlorine that it's made of.

The physical and chemical properties of compounds in general are
very different from the characteristics of any of their constituent
elements in the pure elemental state.

-- Water doesn't act anything like Hydrogen or Oxygen.

-- A candle doesn't act anything like Carbon or Hydrogen.

-- Dry ice doesn't act anything like Carbon or Oxygen.

-- DNA doesn't act anything like Hydrogen, Oxygen, Nitrogen,
   Carbon or Phosphorus.  (We are lucky.)
7 0
3 years ago
In a complete description of a force vector, which is usually not necessary?
Mamont248 [21]

Answer:

Position

Explanation:

A force vector has both magnitude and direction, which can be represented by a line with an arrow head. The length of the line describes magnitude, while the arrows points in the required direction.

generally, the position of a vector is unimportant when describing the vector. Thus, when a force vector is to be described, it is unnecessary to make reference to its original position. Majorly, its magnitude and direction is considered.

5 0
4 years ago
A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the partic
Agata [3.3K]

Answer:

43 m/s

Explanation:

Mass, m = 5 kg

Force, F(t) = 6t² - 4t + 3

To find the speed, we first need to get the acceleration, a.

Force is the product of mass and acceleration. It is given as:

F = ma

Therefore, acceleration is:

a(t) = F(t)/m

a(t) = (6t² - 4t + 3) / 5

a(t) = 1.2t² - 0.8t + 0.6

Acceleration is the differentiation of velocity with respect to time, t. Therefore, to get velocity, v, we integrate a(t):

a(t) = dv(t) / dt

=> v(t) = (1.2/3)t³ - (0.8/2)t² + 0.6t

v(t) = 0.4t³ - 0.4t² + 0.6t

Therefore, at time t = 5secs, velocity is:

v(5) = 0.4 * (5³) - 0.4 * (5²) + 0.6 * 5

v(5) = 50 - 10 + 3

v(5) = 43 m/s

The velocity at time, t = 5 secs is 43 m/s

8 0
3 years ago
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