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larisa86 [58]
3 years ago
6

16.Can you use the SAS Postulate, the AAS Theorem, or both to prove the triangles congruent?

Mathematics
2 answers:
Elza [17]3 years ago
8 0
C I just had this question on a post test..
professor190 [17]3 years ago
6 0
The answer is C

You are already given one angle and one side. Using the vertical angles postulate we know that the two verticle angles are congruent, satisfying the AAS criteria
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1/7x1/7x1/7= 3/7 true or false
Lostsunrise [7]

Answer:

The answer is false

3 0
3 years ago
Read 2 more answers
Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?
garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right).

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be z (x) = \cos x the base formula, where x is measured in sexagesimal degrees. This expression must be transformed by using the following data:

T = 180^{\circ} (Period)

z_{min} = -4 (Minimum)

z_{max} = 5 (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of 2\pi radians. In addition, the following considerations must be taken into account for transformations:

1) x must be replaced by \frac{2\pi\cdot x}{180^{\circ}}. (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

\Delta z = \frac{z_{max}-z_{min}}{2}

\Delta z = \frac{5+4}{2}

\Delta z = \frac{9}{2}

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

z_{m} = \frac{z_{min}+z_{max}}{2}

z_{m} = \frac{1}{2}

The new function is:

z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)

Given that z_{m} = \frac{1}{2}, \Delta z = \frac{9}{2} and T = 180^{\circ}, the outcome is:

z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

8 0
3 years ago
In a store, a sample of 60 pens was selected from a box of 1,200 pens. Of these 60, 4 pens did not work. About how many pens cou
Lapatulllka [165]
Ok so if 1200 total pens and 60 were taken that's a ratio of 1200/60=20

out of 60pens 4 didn't work, again ratio is 4/60=1/15 so about 1/15 of the pens didn't work. 

so we have 1200pens * 1/15broken ratio = 80 pens or we can say 

20*4=80pens won't work from 20 groups of 60 and 4 out of 60 not working is 20*4=80 not working from total batch of 1200.

hope this helps you some! thank you!!!!!!!!!
3 0
3 years ago
How do I solve this equation?
frosja888 [35]

Answer:

x=-3/11

Step-by-step explanation:

(x+3)/5 +2x=0

Multiply both sides by 5 to get rid of the fraction

5*( x+3)/5 +5*2x=0*5

x+3 + 10x =0

Combine like terms

11x +3 = 0

Subtract 3 from both sides

11x+3-3 =0-3

11x = -3

Divide by 11

11x/11 = -3/11

x = -3/11

4 0
3 years ago
WILL MARK BRANLIEST! find of the volume of the prism round to the nearest tenth if necessary
vodomira [7]

Answer:

The answer is A. 204.7

Step-by-step explanation:

5 0
3 years ago
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