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Slav-nsk [51]
3 years ago
6

Negative 5 1 half plus 7 3 over 4

Mathematics
1 answer:
erastovalidia [21]3 years ago
8 0

Answer:

2 \dfrac{1}{4}

Step-by-step explanation:

-5 \dfrac{1}{2} + 7 \dfrac{3}{4} =

= -5 \dfrac{2}{4} + 7 \dfrac{3}{4}

= 7 \dfrac{3}{4} - 5 \dfrac{2}{4}

= 2 \dfrac{1}{4}

You might be interested in
Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour. She also does yard work for $12 per hour. Li
Sedaia [141]
Hello,

As the question states, let r be the number of hours worked at the restaurant, and y be the number of hours of yard work. We know that she can only work a maximum of 15 hours per work total, and that at she must work at least 5 hours in the restaurant. Therefore:r + y ≤ 15r ≥ 5We also know that she wants to earn at least 120 dollars, earning $8/hr in the restaurant and $12/hr in the yard:8r + 12y ≥ 120
What is the maximum of hours Lia can work in the restaurant and still make at leas 120 hours? Lia's parents won't let her work more than 15 hours, so we know that the answer won't be higher than 15.If she worked all 15 hours in the restaurant, she would make 8*15 = 120.The maximum number of hours she can work in the restaurant is therefore 15 hours
What is the maximum amount of money Lia can earn in a week? Lia has to work a minimum of 5 hours in the restaurant. She makes more money doing yard work, so she should devote the rest of her available work hours to yard work. That means that, given her 15 hour work limit, she will maximize her income by working 5 hours in the restaurant and 10 hours in the yard. 5*8 + 10*12 = 40 + 120 = 160The most she can make is 160 dollars, working 5 hours in the restaurant and 10 hours in the yard

Hope this helps

~Girlygir101~
4 0
3 years ago
Ellis is painting wooden fenceposts before putting them in his yard. They are each 5 feet tall and have a diameter of 1 foot. Th
maksim [4K]

Answer:

Step-by-step explanation:

Comment

The first step is to find the surface area of 1 fence post.

The formula is

Area_ends = 2 pi r^2 for the ends.

Area_body = 2*pi*r * h

Givens

r = d/2          r is the radius ; d is the diameter

r = 1/2 foot

h = 10 feet

Solution

1 fence post

Area = ends + area body

Area =  2*3.14 * (1/2)^2 + 2 * pi * r * h

Area = 2*3.14* (1/2)^2 + 2 * 3.14 * 1/2 * 10

Area = 1.57 + 31.4

Area = 32,97 square feet.

10 fence posts

10*32.97 = 329.7 square feet

Answer

10 fence posts have 329.7 square feet in area.

           

4 0
2 years ago
Read 2 more answers
I don’t get 15a. The t^5 is confusing me
kondor19780726 [428]

15a is non-exponential because the variable is not in the exponent

Instead, this is a polynomial function. It can also be called a power function as power functions are in the form a*x^b where 'a' and 'b' are fixed numbers.

3 0
3 years ago
Someone help please! Determine the intercept of the line that passes through the following points ​
storchak [24]

Answer:

x: (-5.0)

y: (0, -17.5)

Step-by-step explanation:

The x-intercept of the line is when y=0. In the table is the point (-5,0). This is the x-intercept.

To find the y-intercept, find when x=0. Write an equation for the table in y=mx + b. Find the slope between two points first.

m = \frac{y_2-y_1}{x_2-x_1} = \frac{7-0}{-7--5} =\frac{7}{-7+5}=-\frac{7}{2} = -3.5

The slope is -3.5. So the equation is

y - 7 = -3.5(x--7)

y - 7 = -3.5 (x+7)

y - 7 = -3.5x - 24.5

y = 3.5x - 17.5

Since it is in y=mx+b, b= -17.5 and this is the y-intercept.

5 0
3 years ago
For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x
Alla [95]
The <u>correct answer</u> is:

D) \left \{ {{2x-y=7} \atop {2x+7y=31}} \right..

Explanation:

We solve each system to find the correct answer.

<u>For A:</u>
\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.

Since we have the coefficients of both variables the same, we will use <u>elimination </u>to solve this.  

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. &#10;\\&#10;\\6x=23

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is <u>not the x-coordinate</u> of the answer we are looking for, so <u>A is not correct</u>.

<u>For B</u>:
\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.

For this equation, it will be easier to isolate a variable and use <u>substitution</u>, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>B is not correct</u>.

<u>For C</u>:
Since the coefficient of x in the second equation is 1, we will use <u>substitution</u> again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>C is not correct</u>.  

<u>For D</u>:
Since the coefficients of x are the same in each equation, we will use <u>elimination</u>.  We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. &#10;\\&#10;\\-8y=-24

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate  Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so <u>D is the correct answer</u>.
7 0
3 years ago
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