Answer:
A 12-kg load stretches an elastic the belt 0.03m
Step-by-step explanation:
we know A 8-kg load stretches an elastic belt 0.02 m.
=> 0.02 / 8 = 0.0025
so A 1-kg load can stretch an elastic belt 0.02 m.
=> 12 * 0.0025 = 0.03 m
A 12-kg load stretches an elastic the belt 0.03m
67 percent is your answer
Answer:
nike its observational
Step-by-step explanation:
The area of a sector of a circle can be calculated by using this formula:
A=(n/360)*pi*r^2
where n is the measure of the central angle of the sector in degrees. Since we are already given with the measurement of the central angle, we can substitute this to the above formula:
A=(30/360)*pi*r^2
Taking the value of pi as 3.14, then
A=(1/12)*3.14*r^2
A=0.2617*r^2
Just plug in the value of r. and you will get the area of the sector. Hope this helps!