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Gemiola [76]
3 years ago
7

Can someone please help me solve this problem?

Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

9514 1404 393

Answer:

  true for all values of d; an infinite number of solutions

Step-by-step explanation:

Most folks find it convenient to eliminate the fractions as a first step. Here, we can do that by multiplying the equation by 12.

  4(2d) +(d +3) = 3(3d +1)

  9d +3 = 9d +3

This is true for all values of d. The equation has an infinite number of solutions.

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Factor the trinomial in to 2 sets of parentheses <br> 12a squared minus 13a minus 35
Juliette [100K]
It can't be factored because there are no 2 numbers that when you multiply you get 35 and when you add you get 13.
8 0
3 years ago
______1. 2 + 3 = 9 ______2. 4 &gt; 5 + 7 ______3. 9 = 12 + 2 ______4. 2 − 3 ≥ 2 ______5. 61 ≠ 5 − 12
Makovka662 [10]

Answer:

1. Not True

2. Not True

3. Not True

4. Not True

5. True

Step-by-step explanation:

As given,

1.

2 + 3 = 9

⇒ 5 = 9

Not True

2.

4 > 5 + 7

⇒4 > 12

Not True

3.

9 = 12 + 2

⇒9 = 14

Not True

4.

2 - 3 ≥ 2

-1 ≥ 2

Not True

5.

61 ≠ 5 - 12

⇒61 ≠ -7

True

5 0
3 years ago
Suppose a family has three children of different ages. We assume that all combinations of boys and girls are equally likely. (a)
Ivan

Answer:

a) There are 8 possible combinations and each probability is 1/8.

b) The probability that it is a boy given that there are two girls is 3/8

Step-by-step explanation:

a) The sample space is given by:

BBB (3 boys)

BBG (Boy, boy, girl)

BGB (Boy, girl, boy)

BGG (Boy, girl, girl)

GBB (girl, boy, boy)

GBG (girl, boy, girl)

GGB (girl, girl, boy)

GGG (3 girls)

The probability of each combination is the same:

P(BBB)=P(B∩B∩B)=\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{1}{8}

2) There are three possible combinations in which there are 2 girls and 1 boy:

BGG, GBG, GGB

So the probability is given by:

P(BGG ∪ GBG ∪ GGB)=\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{3}{8}

6 0
3 years ago
On a number​ line, suppose point E has a coordinate of 2​, and EGequals5. What are the possible coordinates of point​ G?
Ivan

Answer:

-3, 7

Step-by-step explanation:

EG = 5, so the distance between E and G is five.

G can be 5 units to the right of E:

2 + 5 = 7

G has coordinate 7.

G can be 5 units to the left of E:

2 - 5 = -3

G has coordinate -3.

Answer: -3, 7

6 0
3 years ago
Which of these is a solution to the equation 1/8 = 2/5 times x<br> 17/40<br> 2/40<br> 5/16<br> 11/40
solniwko [45]

Answer:

the answer to this is 5/16

7 0
3 years ago
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