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Gemiola [76]
3 years ago
7

Can someone please help me solve this problem?

Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

9514 1404 393

Answer:

  true for all values of d; an infinite number of solutions

Step-by-step explanation:

Most folks find it convenient to eliminate the fractions as a first step. Here, we can do that by multiplying the equation by 12.

  4(2d) +(d +3) = 3(3d +1)

  9d +3 = 9d +3

This is true for all values of d. The equation has an infinite number of solutions.

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208

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Find the slope of each line.
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A is 1:2 B is 3:1 C is 2:3

Step-by-step explanation:

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Do the sides 4, 5, and 6 form a Pythagorean Triple?
NemiM [27]

Answer:

They do not form a Pythagorean Triple.

If it was a Triple,  4^2+5^2 should equal 6^2.

4^2+5^2=16+25=41

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Step-by-step explanation:

8 0
2 years ago
Two trains travel at right angles to each other after leaving the same train station at the same time. Two hours later they are
Alex787 [66]

Answer:

15 miles per hour is the speed of the slower train.

Step-by-step explanation:

As given in the figure attached,

Let the speed of train 1 is v and train 2 is u.

Therefore, distance traveled in 2 hours by train 1 will be = 2v miles

and distance traveled by train 2 will be = 2u miles

Now we can see in the figure a right angle triangle is formed by the two trains.

AB² + BC² = AC²

(2v)² + (2u)²= (65.30)²

4v² + 4u² = 4264.09

Now we divide this equation by 4

v² + u² = 1066.02

If speed of the slower train is v miles per hour then as per statement of the question.

u = v - 14

v = u + 14

By putting the value of v in the equation

(u + 14)² + u² = 1066

u² + 196 + 28u + u² = 1066

2u² + 28u + 196 = 1066

2u² + 28u + 196 - 1066 = 0

2u² + 28u - 870 = 0

By diving this equation by 2

u² + 14u - 435 = 0

u² + 29u - 15u - 435 = 0

u(u + 29) - 15(u + 29) = 0

(u + 29)(u - 15) = 0

u = -29, 15

Since speed can not be with negative notation so u = 15 miles per hour will be the speed.

Therefore, 15 miles per hour is the speed of the slower train.

5 0
3 years ago
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