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saveliy_v [14]
2 years ago
7

3 out of 10 children played outside, 4 out of 11 children played outside

Mathematics
2 answers:
jeka942 years ago
6 0

Answer:

sorry i dont really understand the qustion.

Step-by-step explanation:

do you mind clarifying? im happy to help!

anzhelika [568]2 years ago
6 0
10-3=7 //

11-4=7
Great jobbb
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Find the perimeter of following figure. 2 yd ,2yd ,5yd and 4 yd.
Gnesinka [82]

Answer:

13yd

Step-by-step explanation:

Perimeter is all the side lengths added

5 0
2 years ago
What is d if <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3d-2%7D%7B8%7D%20%3D%20-d%2B16%5Cfrac%7B1%7D%7B4%7D" id="TexFormula1" t
Harlamova29_29 [7]

Answer: d=12

Step-by-step explanation:

\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}

Multiply both parts of the equation by 8:

\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\

Divide both parts of the equation by 11:

d=12

8 0
1 year ago
Please look at picture attached! i will mark you brainlyest if right!
katrin2010 [14]
Amp is the number in front of sine so its 1/2 aka D :)
8 0
2 years ago
The length of a rectangle is 8 m more than 6 times the width. The perimeter is 156 m. Find width.
Alla [95]
<span>width = x
</span><span>length = 6x + 8 

x + 6x + 8 = 156/2
7x + 8 = 78
7x = 78 - 8
7x = 70
x = 70/7
x = 10 m  </span>← width
5 0
3 years ago
In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal
soldier1979 [14.2K]

Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for  95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

So, we have

CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)

CI= (39.04 - 2.513,39.04 + 2.513)

CI= (36.527,41.553)

Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).

8 0
3 years ago
Read 2 more answers
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