Answer:
The one you are on, f(x+2)+4
Step-by-step explanation:
First, we can see by the 0 point that it is just moved up by 4 and not left or right any, so we want to see how it has changed without the +4.
in g(x) the x changes by two, 0 to 2, and the y changes by one, 4 to 5.
Hopefully you can tell what the function being manipulated is. It is x^3 so if we write that instead of f(x) in the answers the first one for instance would be (x/3)^3-4. (let me know if that doesn't make sense)
SInce we already know it's being moved up by 4, we know it's one of those with +4 at the end. It's easy enough to guess and check, but the process to find the answer is pretty easy. We also know that at 2, the change is 1. So without the +4 at the end, what would let us change 8 to 1? dividing it by 8, which is also 2^3. so that means (2/2)^3. So the answer is we want f(x/2) witht he +4 at the end.
Hopefully that made sense, I'd be happy to explain further if you need though
Answer:
23. a-T b-F
24. Words- *3* times the number of *feet*
Variable- Let *y* represent the number of *yards*
Model- (I can't do it)
Expression- The number of feet in*3* yards is given by the expression *3y*
25. 7.8
26. 8.3
27. 14.5
28. Yes. The communitive property tells us that we can switch any two numbers in a multiplication or addition problem
*I did that page like a month ago*
Answer:
B. 3.6 x 10^3
Step-by-step explanation:
(1.2 x 10^-2) x (3 x 10^5)
When we multiply terms with powers , we multiply the factors out front and add the exponents
a * 10^b * c* 10^d = ac * 10^(b+d)
(1.2 x 10^-2) x (3 x 10^5) = (1.2* 3) * 10^(-2+5)
= 3.6 * 10 ^3
Answer:
The two odd numbers are 15 and 17
Step-by-step explanation:
Given
<em>Let the odd numbers be represented with x and y</em>
<em>Let x be the greater number</em>
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<em>Required</em>
Find x and y
Since x and y are consecutive odd numbers and x is greater, then

Substitute y + 2 for x in
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Collect Like Terms
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<em></em>
<em></em>
Divide both sides by 6



Substitute 15 for y in 


<em>Hence; the two odd numbers are 15 and 17</em>