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Bad White [126]
3 years ago
15

Percy works two part-time jobs to help pay for college classes. On Monday, he works 3 hours at the library and 2 hours at the co

ffee cart and earns $36.50. On Tuesday, he works 2 hours at the library and 5 hours at the coffee cart and earns $50. His hourly wage at the library, x, and hourly wage at the coffee cart, y, can be determined using the system of equations below. 3x + 2y = 36.50 2x + 5y = 50.00 At which job does Percy earn the greater hourly wage? How much does Percy earn each hour at this job? Percy earns a greater hourly wage of $7.00 at the library. Percy earns a greater hourly wage of $7.00 at the coffee cart. Percy earns a greater hourly wage of $7.50 at the library. Percy earns a greater hourly wage of $7.50 at the coffee cart.
Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0
To solve the system, the best way to do it is by eliminatiion.  Multiply the first equation by -2 and the second equation by 3.  This changes the system to -6x-4y= -73 and 6x+15y= 150.  When you add those together, the x's are eliminated, leaving 11y = 77 and y = 7.  Sub that in to any one of the above equations to solve for x.  6x + 15(77) = 150 and 6x + 105 = 150.  6x = 45 and x=7.5.  If x is the library and y is the coffee cart, then he makes more at the library.  Your choices aren't numbered, but it's the third one.
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<u>Answer:</u>

<u>For a:</u> The probability of getting a red or blue ball is 0.48

<u>For b:</u> The probability of getting a white, blue or orange ball is 0.81

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<u>Step-by-step explanation:</u>

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}     .......(1)

We are given:

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Total balls in a box = [12 + 18 + 19 + 15] = 64

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Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48

  • <u>For b:</u>

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

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Putting values in equation 1, we get:

\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81

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\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52

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