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4 years ago

How many total atoms from Carbon are present on the reactant side?

Chemistry

1 answer:

bogdanovich [222]4 years ago

7 0

Answer:

2 carbon atoms/molecules are present on the reactant side.

hope it helps!

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What is the best description of a molecule?

finlep [7]

Answer:

Three or more atoms bonded together

Explanation:

A molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds

7 0

3 years ago

M is a mysterious element whose molar mass is 141.0 g/mol. When combined with oxygen, the formula of the compound is M2O5. What

Alex Ar [27]

Answer:

I d k

Explanation:

7 0

3 years ago

Assuming steam to be an ideal gas, calculate its specific volume and density at a pressure of 90 lb/in2 and a temperature of 650

Vitek1552 [10]

Answer:

1) Sv = 0.4584 m³/Kg...assuming steam as an ideal gas

% deviation from the values in the steam tables

⇒ % dev = 45 %

2) mass air = 272.617 Kg; assuming air to be an ideal gas

Explanation:

ideal gas:

PV = RTn

molar volume:

⇒ V/n = RT/P

∴ P = 90 psi * ( 0.06895 bar/psi ) = 6.2055 bar

∴ T = 650 F = 343.33 °C = 616.33 K

∴ R = 0.08314 bar.L/mol.K

⇒ V/n = (( 0.08314 )*(616.33 K )) / 6.2055 bar

⇒ V/n = 8.2574 L/mol * ( m³/1000L ) = 8.2574 E-3 m³/mol

specific volume ( Sv ):

∴ Mw = 18.01528 g/mol

⇒ Sv = 8.2574 E-3 m³/mol * ( mol / 18.01528 g ) * ( 1000 g/Kg )

⇒ Sv = 0.4584 m³/Kg

steam table:

∴ P = 6.2055 bar ≅ 6 bar → Sv = 0.3157 m³/Kg

⇒ % deviation = (( 0.4584 - 0.3157 ) / 0.3157) * 100

⇒ % dev = 45.2 %; significant value, assuming steam to be a ideal gas

2) mass air, assuming ideal gas:

∴ V = 20ft * 35ft * 10ft = 7000ft³ * ( 28.3168 L/ft³ ) = 198217.6 L

∴ P = 17 psi * ( 0.06895 bar/psi ) = 1.172 bar

∴ T = 75 °F = 23.89 °C = 296.89 K

∴ R = 0.08314 bar.L/K.mol

⇒ n air = PV/RT = (( 1.172 )*( 198217.6 )) / (( 0.08314 )*( 296.89 ))

⇒ n air = 9411.616 mol air

∴ Mw air = 28.966 g/mol

⇒ mass air = 9411.616 mol * ( 28.966 g/mol ) = 272616.892 g = 272.617 Kg

7 0

3 years ago

How many liters of 0.3m h3po4 are needed to neutralize 3.5l of 3m naoh

irga5000 [103]

Answer:

$V_{acid}=11.7L$

Explanation:

Hello,

In this case, given the reaction:

$3NaOH+H_3PO_4\rightarrow Na_3PO_4+3H_2O$

We notice a 3:1 molar ratio between sodium hydroxide and phosphoric acid, therefore, at the equivalence point we have:

$n_{base}=3*n_{acid}$

That in terms of molarity is:

$M_{base}V_{base}=3*M_{acid}V_{acid}$

Se we solve for the volume of acid:

$V_{acid}=\frac{M_{base}V_{base}}{3*M_{acid}} =\frac{3M*3.5L}{3*0.3M}\\ \\V_{acid}=11.7L$

Best regards.

4 0

3 years ago

Read 2 more answers

A truckload of apples weighs 2550 lbs. If 5 (exact) apples weigh 1250 g, how many apples are in the truck?

egoroff_w [7]

Answer:

There are 4,626 apples in the truck.

Explanation:

Mass of 5 apples = 1250

Mass of an apple = $\frac{1250 g}{5}=250 g$

Mass of apples in the truck = 2550 lbs

1 lbs = 453.592 g

$2550 lbs=2550\times 453.592 g$

Let the number of apples with mass of 2550 lbs be a.

$a\times 250 g=2550\times 453.592 g$

$a=\frac{2550\times 453.592 g}{250 g}=4,626.63$

4,626.63 ≈ 4,626

So, there are 4,626 apples in the truck.

3 0

3 years ago