To find solubility, we need calculate how much potassium sulfate will be dissolved at 100 g of water.
12 g potassium sulfate ------ 75 g water
x g potassium sulfate --------100 g water
x=12*100/75 = 16g
So, solubility of potassium sulfate at 60⁰ C is 16 g potassium sulfate per 100 g of water.
Isotopes are defined as atoms of same element with different mass number and same atomic number.
Here, atomic number is equal to number of protons and number of electrons, it is denoted by symbol Z thus,

and, mass number is equal to sum of number of protons and neutrons, it is denoted by symbol A thus,

The three isotopes of tin are given, Sn-116, Sn-120 and Sn-126, mass number for these three isotopes is 116, 120 and 126 respectively. Since, they are isotopes thus, atomic number remains the same that is 50.
Since,
thus, number of protons and electrons will be 50.
For Sn-116,

Or,

Or,

For Sn-120,

For Sn-126,

Therefore, mass number, number of protons, electrons and neutrons in all three isotopes are:
Sn-116:
Mass number= 116
Protons=50
neutrons=66
electrons=50
Sn-120:
Protons=50
neutrons=70
electrons=50
Sn-126:
Protons=50
neutrons=76
electrons=50
Answer:
Explanation:
Flame test:
The metals ions can be detected through the flame test. Different ions gives different colors when heated on flame. Tom perform the flame test following steps should follow:
1. Dip a wire loop in the solution of compound which is going to be tested.
2. After dipping put the loop of wire on bunsen burner flame.
3. Observe the color of flame.
4. Record the flame color produce by compound
Color produce by metals:
Red = Lithium, zirconium, strontium, mercury, Rubidium (red violet)
Orange-red = calcium
Yellow = sodium, iron (brownish yellow)
Green = green
Blue = cesium. arsenic, copper, tantalum, indium, lead
Violet = potassium (lilac)
Answer:
For the most part, non-metals (excluding Nobel gases) are the most likely to form covalent bonds. Pure covalent bonds are formed between atoms with the same electronegativity, ie. they are trying to hold on to the electrons in the bond with the same strength.