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kramer
3 years ago
7

What fraction of a Sr-90 sample remains unchanged after 87.3 years

Chemistry
1 answer:
jolli1 [7]3 years ago
8 0
The answer is 1/8.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
<span>t_{1/2} = 28.8 years

We need:
n = ?
x = ?
</span>
We could first use the second equation, to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{87.3 years}{28.8 years}
⇒ n=3.03
<span>⇒ n ≈ 3
</span>
Now we can use the first equation to calculate the remained amount of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^3
⇒x= \frac{1}{8}<span>
</span>
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Which solution below yields the lowest final concentration of a sodium hydroxide solution prepared by diluting 50.00 mL of conce
Firdavs [7]

Answer:

The answer to your question is: letter D. 1.33 L

Explanation:

Data

V1 = 50 ml

C1 = 19.3

To solve this problem use the formula  C₁V₁ = C₂V₂

                            C2 = C1V1 / V2

C = concentration

V = volume

a) 1.15 L

                     C2 = (19.3)(50) / 1150

                      C2 = 0.84 M

b) No right answer

c) V2= 0.80 L

                     C2 = (19.3)(50) / 800

                     C2 = 1.2 M

d) V2 = 1.33 L

                        C2 = (19.3)(50) / 1330

                       C2 = 0.72 M

e) V2 = 350 ml

                         C2 = (19.3)(50) / 350

                         C2 = 2.75 M  

3 0
3 years ago
Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How ma
Katen [24]

Answer: 12.0 milliliters of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn.

Explanation:

moles =\frac{\text {given mass}}{\text {Molar mass}}

moles of zinc =\frac{2.55g}{65.38g/mol}=0.0390moles

The balanced chemical equation is :

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

According to stoichiometry:

1 mole of zinc reacts with = 2 moles of HCl

Thus 0.0390 moles of zinc reacts with = \frac{2}{1}\times 0.0390=0.0780 moles of HCl

To calculate the volume for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}     .....(1)

Molarity of HCl solution = 6.50 M

Volume of solution = ?

Putting values in equation 1, we get:

6.50M=\frac{0.0780\times 1000}{\text{Volume of solution in ml}}

{\text{Volume of solution in ml}}=12.0ml

Thus 12.0 ml of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn

3 0
2 years ago
Calculate the molar mass of a compound if 0.372 mole of it has a mass of 152g​
Snowcat [4.5K]

Answer:

409 g/mol

Explanation:

you divide the mass by the moles to get the molar mass

5 0
3 years ago
1. What is a source of new alleles in natural populations?
scoray [572]

Explanation:

Generally, mating outside of a given population can give different alleles. Mutations and the crossing over of chromatids can add difference to the genetic pool.

8 0
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During meiosis, only one chromosome from each homologous is passed on to the offspring. What does this help increase?
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This helps increase variation in the offspring.
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