
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Find 1/9 :
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

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Find 9/9 :
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

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Answer: The total amount is $324.-----------------------------------------------
Yeah it would be A. because x approaching infinity is to the right of the graph, and since there is a horizontal asymptote at -3 then its correct
Given that the number of years should be represented with x, the number of fish in the pond after x years should best be represented with f(x). The equation that would best show the given scenario in the problem above is,
f(x) = 500(2^x)
From the given, 500 is used as the initial population of the fish.
Answer:
y = 12
Step-by-step explanation:
y = 3x2+6
= 6+6
= 12
y = 12