Answer:
Step-by-step explanation:
yes i think so
Answer:
hmmmmm... thats a tough one
its probably ur mom
Step-by-step explanation:
do you need to include the wiggle infront of the first bracket? if not;
(x+1) ÷ [(x^2+2) x (2x-3dx)]
x^2 x 2x = 2x^3
x^2 x -3dx = -3dx^3
2 x 2x = 4x
2 x -3dx = - 6dx
i cant find a way to make it equal 0 so i think the answer is just
x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction
You have a 16.7% chance of rolling doubles
Answer:
a= 
or 
Step-by-step explanation:
Equate the equation to zero
-9a+2=0
-5a-4a+2=0
5a(2a-1)-2(2a-1)=0
Write out the factors
(5a-2)(2a-1)=0
Then equate each factor to zero
5a-2=0 OR 2a-1=0
5a=2 OR 2a=1
a= OR a=
a= or
