Equation : 3s + 4p = $26
Answer : 2 sodas and 5 bags of popcorn.
The equation would be 3s + 4p = $26. 3s is the $3 for every soda and 4p is $4 for every bag of popcorn.
Shana bought 2 sodas and 5 bags of popcorn. 3 x 2 is 6 and 5 x 4 is 20 which would equal $26. They also equal to the 7 things because of the 2 sodas and 5 bags.
Observe the graph below. This graph represents the scenario.
The question is ill formated, the complete question is
In a simulation, a moving object accelerates from rest to 4 meters per second in 2 seconds. For the following three seconds, it increases linearly until it reaches a speed of 10 meters per second. Following three seconds at that speed (acceleration = 0), the item progressively decelerates until it comes to rest two seconds later. Draw the graph of this scenario for 10 seconds?
I'll describe how the graph may show.
It will move diagonally upward from time 0 to 2 seconds until it reaches the y axis at a speed of 4 m/s.
Then, from 2 to 5, the position will move up diagonally until it reaches the y axis at a speed of 10 m/s.
The next 5 to 8 seconds will be horizontal.
After that, it will descend diagonally.
Observe the graph below. This graph represents the scenario.
Learn more about Acceleration here-
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2n+4=56
n=26 hope this helps
Answer with Step-by-step explanation:
Given

Differentiating both sides by 'x' we get

Now we know that for an increasing function we have
![f'(x)>0\\\\14cos(2x)+7cos(x)>0\\\\2cos(2x)+cos(x)>0\\\\2(2cos^{2}(x)-1)+cos(x)>0\\\\4cos^{2}(x)+cos(x)-2>0\\\\(2cos(x)+\frac{1}{2})^2-2-\frac{1}{4}>0\\\\(2cos(x)+\frac{1}{2})^2>\frac{9}{4}\\\\2cos(x)>\frac{3}{2}-\frac{1}{2}\\\\\therefore cos(x)>\frac{1}{4}\\\\\therefore x=[0,cos^{-1}(1/4)]\cup [2\pi-cos^{-1}(1/4),2\pi ]](https://tex.z-dn.net/?f=f%27%28x%29%3E0%5C%5C%5C%5C14cos%282x%29%2B7cos%28x%29%3E0%5C%5C%5C%5C2cos%282x%29%2Bcos%28x%29%3E0%5C%5C%5C%5C2%282cos%5E%7B2%7D%28x%29-1%29%2Bcos%28x%29%3E0%5C%5C%5C%5C4cos%5E%7B2%7D%28x%29%2Bcos%28x%29-2%3E0%5C%5C%5C%5C%282cos%28x%29%2B%5Cfrac%7B1%7D%7B2%7D%29%5E2-2-%5Cfrac%7B1%7D%7B4%7D%3E0%5C%5C%5C%5C%282cos%28x%29%2B%5Cfrac%7B1%7D%7B2%7D%29%5E2%3E%5Cfrac%7B9%7D%7B4%7D%5C%5C%5C%5C2cos%28x%29%3E%5Cfrac%7B3%7D%7B2%7D-%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Ctherefore%20cos%28x%29%3E%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%5Ctherefore%20x%3D%5B0%2Ccos%5E%7B-1%7D%281%2F4%29%5D%5Ccup%20%5B2%5Cpi-cos%5E%7B-1%7D%281%2F4%29%2C2%5Cpi%20%5D)
Similarly for decreasing function we have
![[tex]f'(x)](https://tex.z-dn.net/?f=%5Btex%5Df%27%28x%29%3C0%5C%5C%5C%5C%5Ctherefore%20cos%28x%29%3C1%2F4%5C%5C%5C%5Cx%3Ccos%5E%7B-1%7D%28%5Cfrac%7B1%7D%7B4%7D%29%5C%5C%5C%5Cx%3D%5Bcos%5E%7B-1%7D%28%5Cfrac%7B1%7D%7B4%7D%29%2C2%5Cpi%20-cos%5E%7B-1%7D%28%5Cfrac%7B1%7D%7B4%7D%29%5D)
Part b)
To find the extreme points we equate the derivative with 0

Thus point of extrema is only 1.