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Viktor [21]
3 years ago
15

Find the balance in an account when $600 is deposited at 3% compounded annually for 2 years.

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0

Step-by-step explanation:

i belive the the answer would be 10000000

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What is the Volume of the prism? ​
Andru [333]

Answer:

296.4cm

Step-by-step explanation:

you do 9.5cm x 5.2cm x 6cm = 296.4cm

8 0
2 years ago
2. Javier used a microscope to measure the diameter
Elza [17]

Answer:

7 x 10^-5

Step-by-step explanation:

0.00001 is 1 x 10^-5 so multiply that by 7

5 0
4 years ago
Read 2 more answers
How do you do this? plz I really need help.
Vlada [557]
The top two answers are equivalent, while the bottom one is not. You would use distributive property in the parentheses. If both expressions are the same, they are equivalent
7 0
3 years ago
Can anyone help me with this, I gave a picture so you can figure it out
Ivenika [448]

Answer:

X=2

Step-by-step explanation:

If the smaller triangle's base is 1.5ft and the bigger triangle's base is 6ft then in order to find x you have to find how much bigger the big triangle is compared to the small triangle in order to do that you have to divide 6 by 1.5 (6÷1.5)  which is 4 now you know that the bigger triangle is 4 times as big as the smaller triangle now to find X divide the 8 by 4 (since the 8 is on the same side as the X only the 8 is on the bigger triangle) which is 2

6 0
3 years ago
Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°
natima [27]

 

\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0

.

\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}

 

 

5 0
3 years ago
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