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d1i1m1o1n [39]
2 years ago
5

Find Solution Asap BRANLIEST ​

Mathematics
1 answer:
Vlad1618 [11]2 years ago
6 0

\langle- 7,3\rangle\langle 9,7\rangle=\langle-42\rangle

Solution:

Given expression is \langle- 7,3\rangle \cdot\langle 9,7\rangle.

This is a vector dot product.

Let us first know the definition of vector dot product.

<u>Definition of dot product:</u>

The two vectors are \mathrm{u}=\left(u_{1}, u_{2}\right) and \mathrm{v}=\left(v_{1}, v_{2}\right).

The dot product of \mathrm{u}=\left(u_{1}, u_{2}\right) and \mathrm{v}=\left(v_{1}, v_{2}\right) is \mathrm{uv}=\left\langle u_{1} v_{1}, u_{2} v_{2}\right\rangle.

Here, u_{1}=-9, v_{1}=3, u_{2}=9, v_{2}=7

\langle- 7,3\rangle\langle 9,7\rangle=\langle(-7)(9)+(3)(7)\rangle

                   =\langle- 63+21\rangle

                   =\langle- 42\rangle

\langle- 7,3\rangle\langle 9,7\rangle=\langle-42\rangle

Hence the answer is \langle- 7,3\rangle\langle 9,7\rangle=\langle-42\rangle.

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A cash box contains $74 made up of quarters, half-dollars, and one-dollar
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Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

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