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d1i1m1o1n [39]
2 years ago
5

Find Solution Asap BRANLIEST ​

Mathematics
1 answer:
Vlad1618 [11]2 years ago
6 0

\langle- 7,3\rangle\langle 9,7\rangle=\langle-42\rangle

Solution:

Given expression is \langle- 7,3\rangle \cdot\langle 9,7\rangle.

This is a vector dot product.

Let us first know the definition of vector dot product.

<u>Definition of dot product:</u>

The two vectors are \mathrm{u}=\left(u_{1}, u_{2}\right) and \mathrm{v}=\left(v_{1}, v_{2}\right).

The dot product of \mathrm{u}=\left(u_{1}, u_{2}\right) and \mathrm{v}=\left(v_{1}, v_{2}\right) is \mathrm{uv}=\left\langle u_{1} v_{1}, u_{2} v_{2}\right\rangle.

Here, u_{1}=-9, v_{1}=3, u_{2}=9, v_{2}=7

\langle- 7,3\rangle\langle 9,7\rangle=\langle(-7)(9)+(3)(7)\rangle

                   =\langle- 63+21\rangle

                   =\langle- 42\rangle

\langle- 7,3\rangle\langle 9,7\rangle=\langle-42\rangle

Hence the answer is \langle- 7,3\rangle\langle 9,7\rangle=\langle-42\rangle.

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Loss ( L ) = CP - SP

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loss \: percent \:  =  \frac{loss}{CP}  \times 100%

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Which 2 teams scored a total of 100 points, red has 29 points, yellow has 38 points, Green has 41 points, blue has 76 points ora
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L 5.2.3 Quiz: Two-Variable Systems: Substitution
Misha Larkins [42]

Answer:

We get x=3 and y=21

The ordered pair will be: (3,21)

Step-by-step explanation:

We need to use the substitution method to solve the system of equations.

y = 10x-9\\y = x + 18

For substitution method we substitute the value of x or y from one equation to other.

Let:

y = 10x-9--eq(1)\\y = x + 18--eq(2)

Putting value of y from equation 2 into equation 1

y=10x-9\\Put\:y=x+18\\x+18=10x-9\\x-10x=-9-18\\-9x=-27\\x=\frac{-27}{-9}\\x=3

So, we get value of x=3

Now, for finding value of y, We substitute the value of x

Find value of x from equation 2

y=x+18\\x=y-18

Now, putting value of x in equation 1

y=10x-9\\Put\:x=y-18\\y=10(y-18)-9\\y=10y-180-9\\y-10y=-189\\-9y=-189\\y=\frac{-189}{-9}\\y=21

So, we get value of y=21

So, We get x=3 and y=21

The ordered pair will be: (3,21)

6 0
2 years ago
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