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inysia [295]
3 years ago
5

Need the slopes for the green and blue line

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0
The problem isn’t very clear but it looks like -1/4
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HELP ME SOLVE THESE PLEASE
Fittoniya [83]

Answer:

True

Step-by-step explanation:

An input is always anything that equals a sum.

Input: Small-Medium-Large

Output: Prices

7 0
3 years ago
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Select the correct answer.
damaskus [11]

Answer: C: Euros

Step-by-step explanation: We know it is in euros because Germany has not branched off of the EU (European Union), it still uses euros, the currency of all of the countries in the EU.

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3 years ago
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Add the expressions four -2/3 B +1/4 a and 1/2 a+1/6b-7. What is the simplified some?
anzhelika [568]

Answer:

I tried the question and I got. a/4-b/2-5/2

Step-by-step explanation:

I hope this helps

3 0
2 years ago
You know that 4 pizzas will feed 16 people how many pizzas do you need to feed 88 people?
Furkat [3]
You can multiply 16 times what equls 88 and then divide by 4 much more simple than it sounds and also your in high school and u cant solve this problem
6 0
2 years ago
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
2 years ago
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