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2 years ago

It cost Naomi $7.70 to send 154 text messages how many text messages did she send if she spent $5.25

Mathematics

1 answer:

igomit [66]2 years ago

8 0

Answer:

105 text messages

Step-by-step explanation:

7.70 divied by 154 = 0.05

0.05 per text massage

5.25 divided by 0.05 = 105

to check work:

105 times 0.05 = 5.25

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Lauren is reading a novel for English class. The data below shows the number of pages reads, y, in x hours.

strojnjashka [21]

Answer:

Choice B is correct

Step-by-step explanation:

The variable x represents the number of hours;

2, 4, 5, 7, 9

The least value is 2 while the maximum value is 9. The scale to be used must accommodate all these values. The scale can thus begin from 0 to 10. Choice A is incorrect since the values 7 and 9 will not be accommodated in the graph.

The y variable represents the number of pages read;

50, 100, 125, 175, 225

The least value is 50 while the maximum value is 225. The scale to be used must accommodate all these values. The scale can thus begin from 0 to 250. Both choices C and D are incorrect since none of the values will be accommodated in the graph.

7 0

3 years ago

Read 2 more answers

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

First case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

Second case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago

Four runners formed a relay team at Jan’s high school. The team completed the relay in 3.86 minutes. Each runner ran exactly the

xeze [42]

Answer: All four runners ran .96 seconds

Step-by-step explanation: The total time of the four runners, divided by the amount of runners.

3.86/4= .965

6 0

3 years ago

What’s the area of 36 square meters perimeter of 30 meters what’s the width and length of those?

Anvisha [2.4K]

≠ means not equal to
L x w = 36
2L + 2w = 30

1. Find the multiples of 36

1 and 36
2 and 18
3 and 12
4 and 9
6 and 6

2. Figure out which set of numbers multiplied by 2 equals 30.

For 1 and 36:
2(1) + 2(36) = 2 + 72 = 74 ≠ 30

For 2 and 18:
2(2) + 2(18) = 4 + 32 = 36 ≠ 30

For 3 and 12:
2(3) + 2(12) = 6 + 24 = 30

So your answer is 3 and 12

3 0

3 years ago

Please help. Thank you!

katrin2010 [14]

Answer:

3a. ⇒ 2700 cm³

3b. ⇒ 72,900 cm³

3c. ⇒ 27

Step-by-step explanation:

3a.

∵ The model in a shape of square pyramid

∴ Its volume = base area × height

∵ Base shaped square with side length 15 cm

∴ Area of base = 15 × 15 = 225 cm²

∵ The model height = 12 cm

∴ She needs = 225 × 12 = 2,700 cm³ of plaster

3b.

∵ Each dimension in the actual stage = 3 times the model

∴ The side of the square base = 15 × 3 = 45 cm

∴ The height = 12 × 3 = 36 cm

∴ The area of the base = 45 × 45 = 2,025 cm²

∴ She needs = 2025 × 36 = 72,900 cm³ of plaster

3c.

∵ Each length in the actual stage is 3 times the model

∴ The volume of the actual stage = (3)³ the volume of the model

∴ The volume of the actual stage = 27 the volume of the model

To check your answer:

Volume actual ÷ Volume model = 72,900 ÷ 2700 = 27

3 0

3 years ago