From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ
ired to do three welds in a day:
a. what is the probability that none of welds will be defective?
b. what is the probability that exactly two of welds will be defective? 2
c. what is the probability that at least two welds are defective? assume that the condition of each weld is independent of the condition of the other welds.
1 answer:
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Answer:
they can??!!!
Step-by-step explanation:
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The answer is... A hope this helps
Answer:
4/8 or 1/2
Step-by-step explanation:
Convert all size to x/8
1/4=2/8 and 1/2=4/8
Multiply size of beaker by how many there are filled
1/8 * 2= 2/8
2/8*7= 14/8
4/8*3 =12/8
then add all of them together = 28/8
convert 4 liters to 32/8
Subtract 32/8 - 28/8 = 4/8
The answer is d $10,748.68
Answer:
the answer is C
Step-by-step explanation: