Answer:
This person have a 29 % probability to receive a speeding ticket
Step-by-step explanation:
The probability of receive a speeding ticket in one of the traps is equal to the probability of going through that trap during the operation time of the trap.
Like we have four traps, and the probabilities are independent, then the probability of receive a speed ticket in one of them, is the sum of the probability for each trap.
P=P1+P2+P3+P4
The probability of going through a trap during the operation time is obtained by multiplying the probability of passing through the trap by the frequency of operation
Frequency of operation:
TL1 ⇒ 40 % = 0.4
TL2 ⇒ 30 % = 0.3
TL3 ⇒ 20 % = 0.2
TL4 ⇒ 30 % = 0.3
Probability of passing through these locations
PL1 ⇒ 0.3
PL2 ⇒ 0.2
PL3 ⇒ 0.4
PL4 ⇒ 0.1
then,
P1= TL1*PL1
P2= TL2*PL2
P3= TL3*PL3
P4= TL4*PL4
and
P = TL1*PL1 + TL2*PL2 + TL3*PL3 + TL4*PL4 = 0.12 + 0.06 + 0.08 + 0.03 = 0.29 = 29 %
This person have a 29 % probability to receive a speeding ticket
Answer:
11 with a remainder of 11
Step-by-step explanation:
the answer is 11 extra
So convert 3.75 into actual time so 3 hours and 45 minutes. Subtract 3 hrs and 45 min from 11:20 and you get 8:35 am. Hope i helped!!
Answer:
39.
Step-by-step explanation:
We subtract f(1) which is the value of f(x) when x = 1 from f(3), then we divide by 3 - 1.
It is [(f3) - f(1]) / (3 - 1), so
Average rate of change = (3(3)^3 + 1) - (3(1)^3 + 1) / (3 - 1)
= (82 - 4) / 2
= 78 / 2
= 39.
I think the length is ten
