My friend is telling me that "6 2" is 12 but the space doesnt represent a mutiply. Is he right or is he wrong?

Mathematics

2 answers:

Burka [1]2 years ago

8 0

I’m also confused confused

kow [346]2 years ago

5 0

Answer:

Your friend is wrong.

Step-by-step explanation:

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Are these rates equivalent, 96 words typed for 3 minutes; 160 words typed for 5 minutes

monitta

<h2>Greetings</h2>

Answer:

Yes, they are.

Step-by-step explanation:

Lets simplify both rates to the rate typer per minute.

(m is minutes)

3m = 96

Divide both sides by 3:

$\frac{3m}{3} = \frac{96}{3}$

m = 32

So the rate is 32 words per minute.

5m = 160

Divide both sides by 5:

$\frac{5m}{5} = \frac{160}{5}$

m = 32

<h3>So because the rates per minute are the same, they are equivalent.</h3>
<h2>Hope this helps!</h2>

3 0

2 years ago

I need the answer for this problem please

Savatey [412]

Answer:

Step-by-step explanation:

Find all probabilities:

A. False

$Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}$

B. True

$Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}$

C. False

$Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}$

D. False

$Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}$