The answer would be 42
42*3 = 126
126+5 = 131
3(n)+5=131
3(n)+5 -5= 131-5
3(n)=126
3(n)/3= 126/3
n= 42
2 out of 50 are defective.
Divide 2 by 50: 2/50 = 0.04
Now multiply the total quantity by that:
2000 x 0.04 = 80
80 are likely to be defective.
2:3:5
2x+3x+5x=180
10x=180
x=18
2x=36
3x=54
5x=90
Answer:

Step-by-step explanation:
we know that

In this problem we have

substitute the given value in the formula and solve for F




He might be 6 now.
hope this helped :)
plzz tell me if I was wrong