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2 years ago

Pls help me its due today

Mathematics

1 answer:

azamat2 years ago

4 0

Answer:

156

Step-by-step explanation:

These angles would equal each other so just set both equations equal to each other to find x:

x + 104 = 3x

Solve:

104 = 2x Subtract x from 3x

x = 52 Divide 2 from 104

Now that we have found x we can find the measurement of either angle. Let's start with the top:

52 + 104 = 156

Now lets do the bottom:

3(52) = 156

Both angles equal 156, so that means that is the answer!

Hope this helps!!

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Answer:

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Step-by-step explanation:

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3 years ago

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What is the equation of the rational function g(x) and its corresponding slant asymptote?

bija089 [108]

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The alternate hypothesis demonstrates that there are two possible outcomes for the test.

Decision rule: If z > 2.05 or z<-2.05, reject H0

z=2.59

The two-tailed nature of the test is shown by the alternative hypothesis.
The result of the test yields the following P-value: 0.0096

<h3>What is the alternate hypothesis?</h3>

(a)

The alternate hypothesis demonstrates that there are two possible outcomes for the test.

(b)

Here we have

$n_{1}=40,\\\\ \bar{x}_{1}=102,\sigma_{1}=5,n_{2}=50,\bar{x}_{2}=99,\sigma_{2}=6$

(b)

Here the test is two-tailed. So for $\alpha =0.04$ , the critical values of the z-test are -2.05 and 2.05.

Decision rule: If z > 2.05 or z<-2.05, reject H0

(c)

Test statistics will be

$z=\frac{(\bar{x}_{1}-\bar{x}_{2})-(\mu_{1}-\mu_{2})}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}} \\\\\\z=\frac{(102-99)-(0)}{\sqrt{\frac{5^{2}}{40}+\frac{6^{2}}{50}}}$

z=2.59

(d)

The two-tailed nature of the test is shown by the alternative hypothesis.

(e)

The result of the test yields the following P-value: 0.0096

Read more about P-value

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2 years ago

Find the missing endpoint if S is the midpoint RT

Stolb23 [73]

Answer:

10. T(-20, 9)

11. R(-1, -9)

12. D(-6, 5)

Step-by-step explanation:

The relationship between end points and the midpoint can be solved generically for one of the end points. That relation can be used for the different points in these problems.

<h3>generic solution</h3>

The coordinates of midpoint M is related to the coordinates of end points A and B by ...

M = (A +B)/2

This can be solved for end point B, given end point A and midpoint M:

2M = A +B

2M -A = B

Then the generic equation for end point B given end point A and midpoint M is ...

B = 2M -A

In each of the numbered problems, the midpoint and one end point are given. These can be matched with the variables in the above formula, so the solution is simply a matter of arithmetic. Beware all the minus signs.

T = 2R -S

T = 2(-9, 4) -(2, -1) = (2(-9) -2, 2(4) +1)

T = (-20, 9)

R = 2S -T

R = 2(-4, -6) -(-7, -3) = (2(-4) +7, 2(-6) +3)

R = (-1, -9)

B = (A +C)/2 = ((-9, -4) +(-1, 6))/2 = (-9 -1, -4 +6)/2 = (-10, 2)/2

B = (-5, 1) . . . . the missing midpoint of AC

D = 2B -E . . . . the missing end point of BD

D = 2(-5, 1) -(-4, -3) = (2(-5) +4, 2(1) +3)) = (-10 +4, 2 +3)

D = (-6, 5)

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2 years ago