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3 years ago

Over which of the given intervals does g have an average rate of change of zero?

Mathematics

1 answer:

Sergio039 [100]3 years ago

7 0

Answer:

I think is c 2 hope that works

Step-by-step explanation:

please give brainliest :D

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n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,

Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

$A = Pe^{rt}$

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

$A=2400 e^{0.0168\times 20}$

$=2400 e^{0.336}$

$= 3358.4136$

$\approx 3358$

6 0

3 years ago

HELP ASAP with this question

ELEN [110]

This took a while since I had to do a lil' work.
Answer is C.

6 0

3 years ago

Read 2 more answers

Which of the following is the value or PQ

liberstina [14]

Answer:

B. 61

Step-by-step explanation:

Given:

∆PQR ≅ ∆PQS

PQ = 2x + 41

QS = 7x - 24

QR = 3x + 16

Required:

Numerical value of PQ

SOLUTION:

First, create an equation to find the value of x as follows:

Since both triangles are congruent, therefore:

QS = QR

7x - 24 = 3x + 16 (Substitution)

Collect like terms

7x - 3x = 24 + 16

4x = 40

Divide both sides by 4

4x/4 = 40/4

x = 10

Find PQ by plugging x = 10 into PQ = 2x + 41

PQ = 2(10) + 41

PQ = 20 + 41

PQ = 61

3 0

4 years ago

quadrilateral ABCD is dilated by a scale factor of 2 centered around (2,2). Which statement is true about the dilation?

Setler [38]

Answer:

The vertices of the image will have the coordinates

A(-5, 1) → A'(2x-2, 2y-2) → A'(-12, 0)

B(-4, 3) → B'(2x-2, 2y-2) → B'(-10, 4)

C(1, 2) → C'(2x-2, 2y-2) → C'(0, 2)

D(-3, 0) → D'(2x-2, 2y-2) → D'(-8, -2)

Step-by-step explanation:

<em>Note: You missed to mention the vertices of a quadrilateral ABCD. So, I am assuming the following vertices. It would anyways clear your concept.</em>

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Let us suppose

A(-5, 1)

B(-4, 3)

C(1, 2)

D(-3, 0)

We know that the rule of the dilation with the center of dilation at (2,2) by a scale factor of 2 is:

(x, y) → (2x-2, 2y-2)

Therefore, the vertices of the image will have the coordinates

A(-5, 1) → A'(2x-2, 2y-2) → A'(-12, 0)

B(-4, 3) → B'(2x-2, 2y-2) → B'(-10, 4)

C(1, 2) → C'(2x-2, 2y-2) → C'(0, 2)

D(-3, 0) → D'(2x-2, 2y-2) → D'(-8, -2)

6 0

3 years ago

Katarina wrote the standard form of a linear equation as 4x – 2/3 y = 8. Sofiya told her that the equation was not yet in standa

-BARSIC- [3]

The standard form of a linear equation in general is given by:

$ax+by=c$

Now we are given the equation :

$4x-\frac{2}{3}y=8$

In order to convert this into standard equation, we have to eliminate the 3 in the second term on the left side of equation.

Here 3 is in division ,so we have to perform opposite operation of division that is multiplication.

So multiplying both sides by 3 , we have

$12x-2y=24$

So that means option A.Multiply both sides of the equation by 3. The standard form of the equation is 12x – 2y = 24. is the correct advice given by Sofiya.

8 0

3 years ago

Read 2 more answers