Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Answer:
36 personas
Step-by-step explanation:
las 2/5 partes q completaron secundaria tambien finalizaron primaria
con lo cual el tercio que estudio primaria esta dentro del grupo de personas que estudiaron
60*2/5 = 24
24 personas estudiaron
60-24=36
52 quadrilaterals would have 52 ÷ 4 = a
a = your answer.
My answer is reasonable because if you have 52 sides from quadrilaterals you would need to divide by 4 to get the amount of quadrilaterals you have. Check your work by multiplying 4 x a = __ (The blank should be 52)
Greetings!
"<span>What is the general process for solving an equation with one variable?"...
Typically when solving an equation with one variable, your objective is to
isolate the variable on one side of the equation. This can be done adding/subtracting number to cancel them out on one side. You can also multiply/divide coefficients in order to isolate a variable.
Example:</span>
<span>Add
-4 to both sides to isolate the variable.
</span>
<span>
Simplify.
</span>
Divide both sides by
2 to isolate the variable on one side.
Hope this helps.
-Benjamin
Assuming that 2 3 is two-thirds. You will need to fill the measuring cup 9 times.
