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Mathematics

1 answer:

Tomtit [17]3 years ago

6 0

Answer:

The ceiling is lower than 3 meters.

Step-by-step explanation:

In the above, the product is <em>less than</em> 3. In this case, it will not include 3 as a choice, as if it would, the $\leq$ would be used.

This means that x would be any number that is less than 3. The only choice that gives a choice that means less than by the terms definition is A) The ceiling is lower than 3 meters.

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Please help me......<br><br>

LenKa [72]

Answer:

C. m ≥ 9

Step-by-step explanation:

7m -2 ≥ 61

7m ≥ 61+2

7m ≥ 63

m ≥ 63/7

m ≥ 9

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3 years ago

Jane is making a suit which requires 2 5⁄8 yards for the jacket and 1 3⁄4 yards for the skirt. What's the total amount of materi

Ann [662]

The answer is B. 4 3⁄8 yards. The amount of material needed for the jacket is: x = 2 5/8 yd = 2 + 5/8 = 16/8 + 5/8 = (16+5)/8 = 21/8 yd. The amount of material needed for the skirt is: y = 1 3/4 yd = 1 + 3/4 = 4/4 + 3/4 = (4+3)/4 = 7/4 yd. The total amount of material Jane needs is: x + y = 21/8 + 7/4 = 21/8 + 14/8 = (21+14)/8 = 35/8 = (32+3)/8 = 32/8 + 3/8 = 4 + 3/8 = 4 3/8 yd.

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4 years ago

Keenan has 28 CDs and 44 DVDs. What is the ratio of DVDs to CDs?

pantera1 [17]

Answer is D.
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4 0

3 years ago

A fraction becomes 4÷5 if 1 is added to both numerator and denominator. If, however, 5 is subtracted from both numerator and den

tia_tia [17]

Answer:

$\dfrac{7}{9}$

Step-by-step explanation:

$\dfrac{x+1}{y+1}=\dfrac{4}{5}\\\Rightarrow 5x-4y=-1$

$\dfrac{x-5}{y-5}=\dfrac{1}{2}\\\Rightarrow 2x-y=5$

Putting it in matrix form

$\begin{bmatrix}a_{1}&b_{1}\\a_{2}&b_{2}\end{bmatrix}{\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}{c_{1}}\\{c_{2}}\end{bmatrix}\\\Rightarrow\begin{bmatrix}5 & -4\\2 & -1\end{bmatrix}\begin{bmatrix}x\\ y\end{bmatrix}=\begin{bmatrix}-1\\ 5\end{bmatrix}$

From Cramer's rule we have

$x=\dfrac{\begin{vmatrix}c_1 &b_1 \\ c_2 & b_2\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow x=\dfrac{\begin{vmatrix}-1 &-4 \\ 5 & -1\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1\end{vmatrix}}\\\Rightarrow x=\dfrac{1+20}{-5+8}\\\Rightarrow x=7$

$y=\dfrac{\begin{vmatrix}a_1 &c_1 \\ a_2 & c_1\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow y=\dfrac{\begin{vmatrix}5 &-1 \\ 2 & 5\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1 \end{vmatrix}}\\\Rightarrow y=\dfrac{25+2}{-5+8}\\\Rightarrow y=9$