Step 1:
Start by putting

in front of each term
![\frac{d}{dx}[y cos x]= \frac{d}{dx}[5x^2]+ \frac{d}{dx}[ 3y^2]](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%5By%20cos%20x%5D%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B5x%5E2%5D%2B%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%203y%5E2%5D)
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Step 2:
Deal with the terms in 'x' and the constant terms
![\frac{d}{dx}[ycosx]= 10x+ \frac{d}{dx} [3y^2]](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bycosx%5D%3D%2010x%2B%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B3y%5E2%5D%20%20)
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Step 3:
Use the chain rule for the terms in 'y'
![\frac{d}{dx}[ycosx]=10x+6y \frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bycosx%5D%3D10x%2B6y%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%20)
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Step 4:
Use the product rule on the term in 'x' and 'y'


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Step 5:
Rearrange to make

the subject


![[cos(x) - 6y] \frac{dy}{dx}=10x + y sin(y)](https://tex.z-dn.net/?f=%5Bcos%28x%29%20-%206y%5D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%3D10x%20%2B%20y%20sin%28y%29%20)

⇒ Final Answer
The equation of the circle:

(h, k) - center
r - radius
We have:

Substitute:

To factor this quadratic equation into double brackets, you need to find two numbers that add together to equal 10, but also multiply to give you 9. These two numbers can be identified as 1 and 9, which will be the numbers you place in your parentheses as follows:
(x+1)(x+9)
Answer:
a. 450 b. 10078.9097
Step-by-step explanation:
a. go with the formula W=FD
F= force
W= work done
D= distance
b. go with the formula F=mgcos(x)
M= mass
G= gravity constant (9.8)
then get to the normal formula of W=FD after getting the Force
<h3><u>Answer</u> :</h3>
See the attachment for better understanding.
<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u>: Length of string (AC) = 300ft
<u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u><u> </u>: Height of the kite from ground (AB)





Hope it helps !