Answer:
- The temperature of 10°C will be experienced at an altitude of 2.52 km
- The temperature of 0°C will be experienced at an altitude of 4.15 km
Explanation:
Lapse Rate = -6.5°C/km of ascent.
Lapse Rate = Temperature difference/altitude difference
For the 10°C,
Temperature difference = 10 - 27 = -17°C
-6.5 = -17/(difference in altitude between the two points)
Difference in altitude = 17/6.5 = 2.52 km
For 0°C,
Temperature difference = 0 - 27 = - 27°C
-6.5 = -27/(difference in altitude between the two points)
Altitude difference = 27/6.5 = 4.15 km
They are both the waste of the sea and land
Answer:
D
The answer cannot be found until it is known whether q is greater than, less than, or equal to 45°.
Explanation:
Since block moves with constant speed
So, frictional force
f = FCosq
Work done by friction
W = - fd
W = - fd Cos q
The answer may be greater or less than - fdSinq. It depends on the value of q which is less than, or equal to 45°.
The answer is; C
In particular points in the earth’s surface, underground water is naturally heated to steam that can be harness for geothermal energy. The steam that ejects from the ground with high kinetic energy can be used to turn turbines that generate electricity. The underground water is usually heated by the hot rocks beneath that are subjected to the immense heat of magma or the enormous pressure of overlying crust.
Answer:
The moment of inertia of large ring is 2MR².
(A) is correct option.
Explanation:
Given that,
Mass of ring = M
Radius of ring = R
Moment of inertia of a thin ring = MR²
Moment of inertia :
Moment of inertia is the product of the mass of the ring and square of radius of the ring.
We need to calculate the moment of inertia of large ring
Using formula of moment of inertia
Where, 
= moment of inertia at center of mass
M = mass of ring
R = radius of ring
Put the value into the formula
Hence, The moment of inertia of large ring is 2MR².
