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r-ruslan [8.4K]
3 years ago
9

A boy reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 m above the ground as he rele

ases it. Use conversation of energy to find
Physics
1 answer:
Lorico [155]3 years ago
6 0

Explanation:

It is given that,

Speed of the ball, v = 10 m/s

Initial position of ball above ground, h = 20 m

We need to find the ball's maximum height above the ground. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh'            

h'=\dfrac{v^2}{2g}

h'=\dfrac{(10)^2}{2\times 9.8}

h' = 5.1 m

The maximum height above ground,

H = 5.1 + 20

H = 25.1 meters

So, the maximum height reached by the ball is 25.1 meters. Hence, this is the required solution.                                

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A 30 g particle is undergoing simple harmonic motion with an amplitude of 2.0 ✕ 10-3 m and a maximum acceleration of magnitude 8
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Answer:

Explanation:

By using the Newton second law and the position equation for a simple harmonic motion we have

F=ma\\a_{max}=\omega^{2}A\\x=Acos(\omega t+ \phi)\\

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\omega=\sqrt{\frac{a_{max}}{A}}=\sqrt{\frac{8*10^{3}m/s^{2}}{2*10^{-3}}}=2000rad/s

(a).

F=ma=m\omega^{2}Acos(\omega t + \phi)\\F=(30*10^{-3}kg)(2*10^{-3}m)(2000\frac{rad}{s})^{2}cos(2000\frac{rad}{s} t - \frac{\pi}{2})=240N*cos(2000\frac{rad}{s} t - \frac{\pi}{2})

(b). T=\frac{2\pi}{\omega}=\frac{2\pi}{2000}=3.14*10^{-13} s

(c). v_{max}=A\omega=(2*10^{-3}m)(2000\frac{rad}{s})=4\frac{m}{s}

(d). The mecanical energy is the kinetic energy when the velocity is a maximum

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4 years ago
How many times can a three-dimensional object that has a radius of 1,000 units fit something with a radius of 10 units inside of
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Answer:

# _units = 1000

Explanation:

This exercise we can use a direct proportion rule.

If a volume of radius r = 1 is one unit, how many units can fit in a volume of radius 10?

    # _units = V₁₀ / V₁

The volume of a body of radius 1 is

       V₁ = 4/3 π r₁³

        V₁ = 4/3π

the volume of a body of radius r = 10

        V₁₀ = 4/3 π r₂³

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8 0
3 years ago
a length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be
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therefore, the resistance of the original wire was 50 \Omega.
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