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Zina [86]
3 years ago
5

A sports car traveling at 24.7 m/s slows at a constant rate to a stop in 16.00 s. What is the displacement of the sports car in

this time interval? *
Physics
1 answer:
maw [93]3 years ago
5 0

Explanation:

Displacement=Velocity×time

=24.7×16.00

=395.2m

Therefore the displacement within the time interval is 395.2m

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1 m = 39.37 in = 39.37/12 ft = 3.28 ft

V = 1145 k/hr  = 1145k/hr * 6076 ft/k = 6957020 ft / hr

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Check:

88 ft/sec = 60 mph

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1933 ft/sec / (88 ft/sec) * 60 mph = 1318 mph

Also,  1318 / 1145 = 6076 / 5280       as it should

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