Total number of oz of honey = 12 oz. Cost of 12 oz of honey = $5.40. Cost per oz of honey = 5.40 divided 12 = $0.45 per oz. Therefore, a) Cost per ounce of honey = $0.45. b) Number of ounces we can buy for one dollar = 12 divided by 5.40 = 2.22 oz approximatly. c) h = 2.22c, wherr h is the number of ounces of honey for c dollars. c=0.45h, where c is the total cost of h number of ounces of honey. d) Let us take c=0.45h equation for graph the situation. x-axis would be for h number of ounces of honey and y-axis is the total cost c of h ounces of honey. Let us find some values of h and c for the graph. For equation: c=0.45h for h=1,we get c=$0.45. If we plug h=2, we get c= 0.45*2 = $0.90. If we plug h=3, we get c= 0.45*3 = $1.35. Therefore, we would plot (1,0.45), (2,0.90) and (3,1.35) on the graph and draw a straight line.
If an adult ticket costs $10, and a chlid's ticket is $5, then one possible combination of tickets could be 30 adult tickets and 10 children tickets. Another could be to sell 15 adult tickets and 25 children tickets.